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Genrish500 [490]
3 years ago
12

3(x -2 = 3x - 5 is it a no slolution or one solution or x= 0 or infinite

Mathematics
2 answers:
leonid [27]3 years ago
7 0

Answer:

no solution

Step-by-step explanation:

SCORPION-xisa [38]3 years ago
7 0

Answer:

Step-by-step explanation:

3(x-2)=3x-5

3x-6=3x-5 now add 6 to both sides

3x=3x+1 subtract 3x from both sides

0=1

Zero is not equal to one so there is no value of x that satisfies the original equation. There is no solution.

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Use Gauss-Jordan elimination to solve the following linear system.
marysya [2.9K]
Just put the coefients in to a matrix

1x-6y-3z=4
-2x+0y-3z=-8
-2x+2y-3z=-14

\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\-2&2&-3|-14\end{array}\right]
mulstiply 2nd row by -1 and add to 3rd
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&2&0|-6\end{array}\right]
divde last row by 2
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 2rd row by 6 and add to top one
\left[\begin{array}{ccc}1&0&-3|-14\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 1st row by -1 and add to 2nd
\left[\begin{array}{ccc}1&0&-3|-14\\-3&0&0|6\\0&1&0|-3\end{array}\right]
divide 2nd row by -3
\left[\begin{array}{ccc}1&0&-3|-14\\1&0&0|-2\\0&1&0|-3\end{array}\right]
mulstiply 2nd row by -1 and add to 1st row
\left[\begin{array}{ccc}0&0&-3|-12\\1&0&0|-2\\0&1&0|-3\end{array}\right]
divide 1st row by -3
\left[\begin{array}{ccc}0&0&1|4\\1&0&0|-2\\0&1&0|-3\end{array}\right]

rerange
\left[\begin{array}{ccc}1&0&0|-2\\0&1&0|-3\\0&0&1| 4\end{array}\right]

x=-2
y=-3
z=4
(x,y,z)
(-2,-3,4)

B is answer
7 0
3 years ago
Mike had $8.25 in his account. He deposited $2.25 on Tuesday. He then withdrew $5.75 for lunch on Wednesday. How much money does
Andre45 [30]

Answer:

<em>$4.75</em>

Step-by-step explanation:

(had) 8.25 + (deposited) 2.25 = (total) 10.50

10.50 - (withdrew) 5.75 = (total left) 4.75

6 0
3 years ago
Read 2 more answers
Fill in the table of values so that this is a proportional relationship with k=3/2
Zigmanuir [339]

Step-by-step explanation:

the table is non-existent

3 0
3 years ago
Which expression is NOT equivalent to the other three? A) −9 − 7n + 16n B) 9(n − 9) Eliminate C) n − 9 + 8n D) 9n − 9
yuradex [85]

Answer:

The expression is not equivalent to other three is 9(n-9) .

Option (B) is correct .

Step-by-step explanation:

Take first expression

= -9 -7n + 16n

= 9n-9

Take second expression

= 9(n-9)

= 9 × n - 9 × 9

= 9n - 81

Take third expression

= n-9+8n

= 9n-9

Take fourth expression

= 9n-9

Therefore expression is not equivalent to other three is 9(n-9) .

Option (B) is correct .

6 0
4 years ago
Read 2 more answers
Is a parallelogram sometimes always or never a trapezoid
Bond [772]

yes

Step-by-step explanation:

parallelogram are quadrilaterals with two sets of parallel sides. since square must be quadrilaterals with two sets of parallel sides ,then all squares are parallelogram ,a trapezoid is quadrilateral.

8 0
3 years ago
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