The price of the stock of PEV Corporation varies as shown. we have to determine the net charge. Net change is just how much it changed overall, so we will look for all the ups minus all the downs.
Here, "went up" goes with a + sign, and "went down" goes with a - sign.
So, Net charge = 
= 
= 
= 
LCM of 2,3 and 10 is 30
= 
= 
= 
So, the net charge is 
Answer:
24
Step-by-step explanation:
really need more information about the subject, but im assuming its just basic addition.
36-12=24
Given this equation:

That represents t<span>he height of a tree in feet over (x) years. Let's analyze each statement according to figure 1 that shows the graph of this equation.
</span>
The tree's maximum height is limited to 30 ft.
As shown in figure below, the tree is not limited, so this statement is false.
<span>
The tree is initially 2 ft tall
The tree was planted in x = 0, so evaluating the function for this value, we have:
</span>

<span>
<span>So, the tree is initially

tall.
</span>
Therefore this statement is false.
</span>
Between the 5th and 7th years, the tree grows approximately 7 ft.
<span>
if x = 5 then:
</span>

<span>
</span>if x = 7 then:

So, between the 5th and 7th years the height of the tree remains constant
:

This is also a false statement.
<span>
After growing 15 ft, the tree's rate of growth decreases.</span>
It is reasonable to think that the height of this tree finally will be 301ft. Why? well, if x grows without bound, then the term

approaches zero.
Therefore this statement is also false.
Conclusion: After being planted this tree won't grow.
Answer:
$151.80 was the total bill including tip.
Step-by-step explanation:
$126.50 x 20% = $25.30
$126.50 + $25.30 = $151.80
Hey there!
In order to find the additive inverse of any number, regardless if it is real or not, you can simply multiply the number by -1 or negate it.
This should look like this:
-(6-3i)
=-6+3i
Therefore, the additive inverse of 6-3i is -6+3i.
**Note: Keep in mind, when the additive inverse of a number is added to the number, the number equals 0:
(6-3i)+(-6+3i)=0
Hope this helps and have a marvelous day! :)