Answer:
There is no solution (since none has side length of 4 units)
Step-by-step explanation:
If V (-1,1) is one of vertex of a square, then the next vertex to V distance must be the known value of 4
VA: V to (-3,3) = √(-1 - -3)² + (1 - 3)² = √8 = 2.8
VB: to (-5,-3) = √(-1 - -5)² + (1 - -3)² = √32 = 5.7
VC: o (3,3) = √(-1 -3)² + (1 - 3)² = √20 = 4.47
VD: to (-5,3) = √(-1 - -5)² + (1 - 3)² = √20 = 4.47
VE: to (4,5) = √(-1 - 4)² + (1 - 5)² = √41 = 6.4
