Answer:
? I don't get what you're trying to ask, I'm sorry!
Explanation:
Hope you have a good day tho!
Answer:
int count =0;
for(int i=0;i<10;i++)
{
if(myArray[i]>=0)
{
count++;
}
}
cout<<"Number of positive integers is "<<count<<endl;
Explanation:
The above written loop is for counting positive integers in the myArray[].
For counting we have taken a count integer initialized with 0.On iterating over the array if the element is greater than or equal to 0 we consider it as positive and increasing the count.At the end printing the count.
Yes... so it would be 134 seeing as, 128 and 4 both common denominators.. and the offset would be to the 40%
In the C language, letters can be printed as their ASCII value (which is an integer). So there, something like this would print 65 for A.