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3 years ago

The distance a jet travels (s) varies directly with the number of hours (1) flown. A jet

Mathematics

1 answer:

DaniilM [7]3 years ago

3 0

Answer:

Step-by-step explanation:

Soucre: trust me bro

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I really need help with this pls help and show work

ohaa [14]

okay so first we need to multiply 160 on both sides

{18/32(160)=n/160*160 (160 cancels out)}

so once we finish our calculations on the left side we get n equals 90

{n=90}

6 0

3 years ago

The histogram below shows the heights, rounded to the nearest inch, of the members of the Oak High School basketball team. A. 1

Elan Coil [88]

Answer:

Range of player's height = 9 inch

Step-by-step explanation:

Given:

Number of players Height range

4 66-67

8 68 -69

14 70-71

9 72-73

1 74-75

Find:

Range of player's height

Computation:

Range = Maximum value - Minimum Value

Range of player's height = Maximum height of a player - height of a player

Range of player's height = 75 inch - 66 inch

Range of player's height = 9 inch

5 0

3 years ago

A local restaurant purchased 45 pounds of flour at a total cost of $38.25 determine the unit cost per pound

xxTIMURxx [149]

$0.85
38.25/45= .85
TO CHECK
.85 times 45 equals 38.25

7 0

3 years ago

Read 2 more answers

Please help me it is due today

boyakko [2]

Answer:

Step-by-step explanation:

A give me 2'zero

b give me 9'zero

c give 8'zero

d gives 5 zero

e give me 4'zero

for example it give me two zero it 100

or if five 5 zero it 100000

hope this helps

3 0

3 years ago

In order to remove water from a flooded basement, two pumps, each rated at 40 gallons per minute, are used. After half an hour,

Scrat [10]

Answer:

3600 gallons of water was removed from the basement.

Step-by-step explanation:

Given:

Rate of each pump = 40 gallons/min

We need to find find the number of gallons of water removed from the basement.

Solution:

Now Given:

After half an hour, the one pump burns out.

Now we know that;

1 hour = 60 mins

$\frac12$ hour = $\frac{60}{2}=30\ mins$

Now for 30 mins both the pumps were working and removing the water.

So we can say that;

Water remove for first 30 mins = $40\times2\times30=2400\ gallons$

Also Given:

the second pump finishes removing the water half an hour later.

So we can say that;

Water removed for next 30 mins = $40\times 30\times1 =1200\ gallons$

Now we can say that;

Total water removed from the basement is equal to sum of Water remove for first 30 mins and Water removed for next 30 mins .

framing in equation form we get;

Total water removed from the basement = $2400+1200=3600\ gallons.$

Hence 3600 gallons of water was removed from the basement.

6 0

3 years ago