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3 years ago

Can someone help me with a, b, c, and d I would really appreciate it

Mathematics

1 answer:

dsp733 years ago

6 0

Step-by-step explanation:

a. Area = 121 ft²

s² = 121

s = √121

Therefore s = 11 ft

b. Area = 81 yd²

s² = 81

s = √81

Therefore s = 9 yd

c. Area = 324 cm²

s² = 324

s = √324

Therefore s = 18 cm

d. Area = 361 mi²

s² = 361

s = √361

Therefore s = 19 MI

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Number 1d please help me analytical geometry

lesantik [10]

For a) is just the distance formula

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ x}}\quad ,&{{ 1}})\quad 
% (c,d)
B&({{ -4}}\quad ,&{{ 1}})
\end{array}\qquad 
% distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
\sqrt{8} = \sqrt{({{ -4}}-{{ x}})^2 + (1-1)^2}
\end{array}$
-----------------------------------------------------------------------------------------
for b) is also the distance formula, just different coordinates and distance

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ -7}}\quad ,&{{ y}})\quad 
% (c,d)
B&({{ -3}}\quad ,&{{ 4}})
\end{array}\ \ 
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
4\sqrt{2} = \sqrt{(-3-(-7))^2+(4-y)^2}
\end{array}$
--------------------------------------------------------------------------
for c) well... we know AB = BC.... we do have the coordinates for A and B
so... find the distance for AB, that is $\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ -3}}\quad ,&{{ 0}})\quad 
% (c,d)
B&({{ 5}}\quad ,&{{ -2}})
\end{array}\qquad 
% distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\
d=\boxed{?}

\end{array}$

now.. whatever that is, is = BC, so the distance for BC is

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
B&({{ 5}}\quad ,&{{ -2}})\quad 
% (c,d)
C&({{ -13}}\quad ,&{{ y}})
\end{array}\qquad 
% distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\
d=BC\\\\
BC=\boxed{?}

\end{array}$

so... whatever distance you get for AB, set it equals to BC, BC will be in "y-terms" since the C point has a variable in its ordered points

so.. .solve AB = BC for "y"
------------------------------------------------------------------------------------

now d) we know M and N are equidistant to P, that simply means that P is the midpoint of the segment MN

so use the midpoint formula

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
M&({{-2}}\quad ,&{{ 1}})\quad 
% (c,d)
N&({{ x}}\quad ,&{{ 1}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)=P
\\\\\\
$

$\bf \left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)=(1,4)\implies 
\begin{cases}
\cfrac{{{ x_2}} + {{ x_1}}}{2}=1\leftarrow \textit{solve for "x"}\\\\
\cfrac{{{ y_2}} + {{ y_1}}}{2}=4
\end{cases}$

now, for d), you can also just use the distance formula, find the distance for MP, then since MP = PN, find the distance for PN in x-terms and then set it to equal to MP and solve for "x"

7 0

3 years ago

First term is is 22 and the common difference is -13

bonufazy [111]

Answer:

$a_{n}$ = 35 - 13n

Step-by-step explanation:

Assuming you require the n th term formula

The n th term of an arithmetic sequence is

$a_{n}$ = a₁ + (n- 1)d

where a₁ is the first term and d the common difference

Here a₁ = 22 and d = - 13, thus

$a_{n}$ = 22 - 13(n - 1) = 22 - 13n + 13 = 35 - 13n

8 0

2 years ago

Plz help me with this

Lady_Fox [76]

Basically it’s asking when is the function g(x) greater than the function of f(x), which are both graphed on the graph. g(x) needs to be above f(x) for it to be greater, and that is shows between 0-2 and 4+, making the answer A

5 0

3 years ago

What value of x makes the equation 0.2(16x – 48) = -0.4(x – 3) true?

fredd [130]

3.2x-9.6=-.4x+1.2
3.2x=-.4x+10.8
3.6x=10.8
X= 3

5 0

2 years ago

Read 2 more answers

An expression is shown 30×8×103 P.s the three is in top of the 10 What is the value of the expression

lesya692 [45]

Answer: 2.4×10^5

Step-by-step explanation:

30×8×10^3

First multiply and forget about ×10^3 for now:

30×8 = 240

Then add back the ×10^3:

240×10^3

Then simplify:

2.4×10^5

To check the answer:

30×8×10³=

30×8000= 240000

Then simplify:

240000 = 2.4 ×10⁵

8 0

2 years ago