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2 years ago

PLSSSSS HELPPP ASAP WILL GIVE BRAINLEAST 10 POINTS!!

Mathematics

1 answer:

Feliz [49]2 years ago

7 0

I think it’s C. If you turn them both the same way, they look to be around the same size.

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• Trey attended a New Year's Eve event and watched a ball drop at midnight. Prior

jekas [21]

Answer:

x=60.9°

Step-by-step explanation:

Given that the height of ball from the ground is 150ft

The base of the pole with the ball is 80 ft from where Trey is standing

Trey's horizontal line of sight is 6 feet above ground, then;

The height of ball from Trey's horizontal line of sight is;

150ft-6ft = 144ft

To find the angle x, assume a triangle with a base of 80 ft , a height of 144 ft and a slant height that represent the line of sight at an angle x

To get angle x , you apply the tangent of an angle formula where;

tan Ф°= length of opposite site of the angle/length of the adjacent side of the angle

tan x°= 144/80

tan x°= 1.8

x°= tan⁻(1.8)

x°=60.9°

7 0

3 years ago

Find the length of the curve. R(t) = 7t, 3 cos(t), 3 sin(t) , −2 ≤ t ≤ 2

Leviafan [203]

we are given

$r(t)=(7t,3cos(t),3sin(t))$

we can find x , y and z

$x=7t,y=3cos(t),z=3sin(t))$

now, we can use arc length formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

now, we can find derivative

$x'=7,y'=-3sin(t),z'=3cos(t))$

now, we can plug values

and we get

$L=\int _{-2}^2\sqrt{7^2+\left(-3\sin \left(t\right)\right)^2+\left(3\cos \left(t\right)\right)^2}dt$

$L=\int _{-2}^2\sqrt{7^2+9}dt$

$=\sqrt{58}\cdot \:2-\left(-2\sqrt{58}\right)$

$L=4\sqrt{58}$ ...........Answer

8 0

3 years ago

LOL ANOTHER MATH QUESTION ASAP!!!

Inessa05 [86]

Your answer is the first one q

6 0

3 years ago

Read 2 more answers

I’m stuck on this problem

slavikrds [6]

The value of the f(-8) from the given f(x) is 1/53.

According to the statement

we have given that the value of f(x) and with the value of this we hav eto find the value of f(-8).

So, For this purpose,

The given value of f(x) :

The function f(x) is

f(x) = 1 / x^2 -11

Now we find the value of the f(-8) then

For this put Put x is -8 in the f(x) then the equation become

f(x) = 1 / x^2 -11

f(-8) = 1 / (-8)^2 -11

f(-8) = 1 / 64 -11

f(-8) = 1 / 53.

here the value becomes 1/53.

So, The value of the f(-8) from the given f(x) is 1/53.

Learn more about function f(x) here

brainly.com/question/4025726

#SPJ1

4 0

1 year ago

A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6. Find the total area of the pyramid.

Tanzania [10]

The total area of pyramid is 113.569 square units

The equation to find the total area of the pyramid is Total area = base area + lateral area.

Solution:

Given, A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6.

The total area of pyramid is given by:

$A=A_{b}+A_{l}$ ---- eqn 1

Where,

$A_{b} \text { is the base area and } A_{l} \text { is the lateral area }$

The area of base is given as:

$A_{b}=\frac{3 \sqrt{3}}{2} l^{2}$

Where "l" is the side of hexagon.

Substituting we get,

$\begin{array}{l}{A_{b}=\frac{3 \sqrt{3}}{2}(4)^{2}} \\\\ {=\frac{3 \sqrt{3}}{2} \times 16=3 \sqrt{3} \times 8} \\\\ {A_{b}=24 \sqrt{3}}\end{array}$

The lateral area is given as:

$A_{l}=3 b h$

Where,

b: base of the triangle

h: height of the triangle

Substituting we get,

$\begin{array}{l}{A_{l}=3 \times(4) \times(6)} \\\\ {A_{l}=72}\end{array}$

Plugging in the values we found in eqn 1 we get,

$A=24 \sqrt{3}+72$

A = 113.569 square units

Summarizing the results:

The total area of pyramid is 113.569 square units approximately

The equation used to find total area of pyramid is Total area = base area + lateral area.

8 0

3 years ago