What volume would a 200 g sample of gold have, if its density is known to be 19.3

Mathematics

1 answer:

alukav5142 [94]2 years ago

8 0

Answer:

The volume that a 200 g gold sample would have is 10.36 mL.

Step-by-step explanation:

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space. In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

$density=\frac{mass}{volume}$

In this case it is known that the density of gold is 19.3 g / mL. This indicates that in 1 mL there are 19.3 g. Then the following rule of three can be applied: if 19.3 g is contained in 1 mL, how much volume is 200 g of gold?

$volume=\frac{200 g*1mL}{19.3g}$

volume= 10.36 mL

<u><em> The volume that a 200 g gold sample would have is 10.36 mL.</em></u>

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Which represents the solution(s) of the equation x2 = 36?

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Answer:

Step-by-step explanation:

x2 = 36?

solution

x^2-(36)=0

Factoring: x2-36

Check : 36 is the square of 6

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we can factor the whole thing:

(2sin(x) -1)(sin(x)+1) = 0.

Therefore, sin(x) = -1 and sin(x) = 1/2.

For the first one x = 3π/2 and the second is π/6 and 5π/6

So 3π/2, π/6 and 5π/6 are the solutions.

I do kind of have a problem with this because it doesn't mention if you should go over 360°. Otherwise, you have to add in an 2nπ into the equations like 3π/2 + 2nπ; $n \in \mathbb{W}$