Answer:
Plant species it eats
Explanation:
The 1st, 3rd, and 4th are describing its surroundings not the individual grasshopper.
Answer:
That cells are not the building block of life
Explanation:
Copies of the original DNA strand
Answer
RIBOSOMES on the ROUGH ENDOPLASMIC RETICULUM
Explanation:
This is the site of protein synthesis usually find attached to the rough endoplasmic reticulum or freely on the cystosol,
When they are attached to the endoplasmic reticulum they appeared as back dots which makes the surface of ER to appear rough, hence the name ROUGH ER. Smooth ER, lacks Ribosomes, and therefore appears smooth,
Ribosomes are made up of PROTEIN AND RNA.
They are 25nm in diameter;when viewed under high magnification, where theymade up of two sub-units the small and large units.
The protein synthesize by the Ribosomes are passed into the sacs of Rough E.R for transportation,
Basically, a complete Ribosomes is refereed to as 70S for prokaryotic ribosomes and 80S for Eukaryotic Ribisomes.This refers to their sedimentation Co-efficient in Svedberg units,the Eukaryotes sediment faster than the Prokaroytes
Hardy-Weinberg Equation (HW) states that following certain biological tenets or requirements, the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimel. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1
So (p+q)(p+q) algebraically works out to p^2 + 2pq + q^2 = 1, where p^2 = genotype frequency of homozygous dominant individuals, 2pq = genotype frequency of heterozygous individuals, and q^2 = genotype frequency of homozygous recessive individuals.
The problem states that Ptotal = 150 individuals, H frequency (p) = 0.2, and h frequency (q) = 0.8.
So homozygous dominant individuals (HH) = p^2 = (0.2)^2 = 0.04 or 4% of 150 --> 6 people
Heterozygous individuals (Hh) = 2pq = 2(0.2)(0.8) = 0.32 or 32% of 150
--> 48 people
And homozygous recessive individuals (hh) = q^2 = (0.8)^2 = 0.64 = 64% of 150 --> 96 people
Hope that helps you to understand how to solve these types of population genetics problems!
