Use the Pythagorean theorem to find z:
z = √(6^2 + 9^2)
z= √(36 + 81)
z = √117
z = 3√13 = 10.8
Use leg rule to find x:
x/6 = 6/9
Cross multiply:
9x = 36
Divide both sides by 9:
x = 36/9
x = 4
Use Pythagorean theorem to find y:
y = √(6^2 + 4^2)
y= √(36 + 16)
y = √52
y = 2√13 = 7.2
I would use the quadratic formula for this:
x = -b ± √b² - 4ac over 2a
x = 8 ± √64 - 4(1)(0) over 2(1)
x = 8 ± √64 over 2
x = 8 <span>± 8 over 2 [simplify]
x = 4 </span><span>± 4
x1 = 4 + 4 x2 = 4 - 4
x1 = 8 x2 = 0
Thus, the solutions for x would be 0 and 8.</span>
12/x = 15/8
96 = 15x
x= 6.4 or 32/5
