You are helping create goodie bags for a class party. You have bags Reeses and

Help Asap Please!! mark as Brainliest

nekit [7.7K]

1. $\frac{1}{2}$ (10m - 14) + 9 = 12 1. Given

2. 5m - 7 + 9 = 12 2. Distributive Property

3. 5m + 2 = 12 3. Simplify (added like terms)

4. 5m = 10 4. Subtraction Property of Equality

5. m = 2 5. Division Property of Equality

3 0

3 years ago

Read 2 more answers

Thanks for the help

Brrunno [24]

The answer is B.

In the question it says "the intercept of 6" which means the equation has to have +6 in the answer, and there is only one answer choice containing that.

4 0

3 years ago

(08.02)

alukav5142 [94]

Answer:

the median is 80.5

Step-by-step explanation:

first we put them in order

75,76,77,79,80,81,85,86,90,91

the median is the middle number...however, in cases where there are an even number of numbers, ur gonna have 2 middle numbers....so u take the average of those 2 numbers...basically, u add them and divide by 2.

So we have 2 numbers in the middle.....we add them and divide by 2 to get the median.

(80 + 81) / 2 = 161/2 = 80.5 <== the median

8 0

3 years ago

Which of the following comparisons is FALSE?

dybincka [34]

Answer:

A

Step-by-step explanation:

Let's check each one-by-one.

a.

we know 3.79 liters is 1 gallon, so 4 liters IS NOT LESS THAN 1 gallon

THis is false.

b.

We know 1 feet is 0.30 meters, so definitely 1 foot is less than 1 meter.

This is true.

c.

we know around 28.35 grams is 1 ounce, so definitely 25 grams is less than 1 ounce.

THis is true.

d.

We know 1 km is approximately 0.62 miles so 10 km would be around 0.62*10 = 6.2 miles

So definitely 9 miles IS GREATER than 10 km.

THis is true.

So answer choice A is false, only.

4 0

3 years ago

Dylan Rieder is a statistics student investigating whether athletes have better balance than non-athletes for a thesis project.

Kobotan [32]

Answer:

$t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457$

$p_v =P(t_{75}$

Comparing the p value with a significance level for example $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't say that the population mean for the athletes is significantly lower than the population mean for non athletes.

Step-by-step explanation:

Data given and notation

$\bar X_{A}=3.7$ represent the mean for athletes

$\bar X_{NA}=4.1$ represent the mean for non athletes

$s_{A}=1.1$ represent the sample standard deviation for athletes

$s_{NA}=1.3$ represent the sample standard deviation for non athletes

$n_{A}=32$ sample size for the group 2

$n_{NA}=45$ sample size for the group 2

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the population mean for athletes is lower than the population mean for non athletes, the system of hypothesis would be:

Null hypothesis: $\mu_{A}-\mu_{NA}\geq 0$

Alternative hypothesis: $\mu_{A} - \mu_{NA}< 0$

We don't have the population standard deviation's, we can apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{A}-\bar X_{NA})-\Delta}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{NA}}{n_{NA}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457$

P value

We need to find first the degrees of freedom given by:

$df=n_A +n_{NA}-2=32+45-2=75$

Since is a one left tailed test the p value would be:

$p_v =P(t_{75}$

Comparing the p value with a significance level for example $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't say that the population mean for the athletes is significantly lower than the population mean for non athletes.

5 0

3 years ago