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BaLLatris [955]
3 years ago
5

The value of the function at x=-6 is ?

Mathematics
1 answer:
Sholpan [36]3 years ago
7 0

Answer:  x = 6, the y - coordinate is 4, therefore the value of the function when x = 6 is 4.

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What is the name of a shape with two parallel sides and four right angles
Sonja [21]
A square has two parallel sides and four right angles.
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3 years ago
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The area of Kylie's room is 400 square feet. The width of her room is 20 feet. What is the length of her room?
zavuch27 [327]

Answer:

length=20 (Sorry if this is wrong)

Step-by-step explanation:

400÷20=20

3 0
3 years ago
Good afternoon guys and god bless!! does anyone know the answer to this?
SVEN [57.7K]

Answer:

ITS UNDEFINED

Step-by-step explanation:

3 0
3 years ago
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PLEASE PLEASE PLEASE HELP!!
Marta_Voda [28]
Okay I'll try to show it step by step

Step 1. So first you need to recognise that the diagram is a right angled triangle, with the right angle being at the bottom. This means we can do Pythagoras' Theorem.

Step 2. Now that you know you can use Pythagoras' Theorem, you can apply it. If you don't know, the theorem is a² + b² = c², with, in this case, a being 5 and b being 8. This means we can do 5² + 8² = 25 + 64 = 89.

Step 3. From the previous step, we now know that the length of the side including x is √89, and because we know that part of this side is 3, if we subtract 3 from √89 we get the value of x, so: √89 - 3 = 9.434 - 3 = 6.434, which is your answer.

I hope this helps!
5 0
3 years ago
The area of the shaded segment is 100cm^2. Calculate the value of r.
Reil [10]
Hello, 

The formula for finding the area of a circular region is: A=  \frac{ \alpha *r^{2} }{2}

then:
A_{1} = \frac{80*r^{2} }{2}

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

cos(40)= \frac{h}{r}  \\  \\ h= r*cos(40)\\ \\ \\ sen(40)= \frac{b}{r} \\ \\ b=r*sen(40)

Now we can find its area:
A_{2}=2* \frac{b*h}{2}  \\  \\ A_{2}= [r*sen(40)][r*cos(40)]\\  \\A_{2}= r^{2}*sen(40)*cos(40)

The subtraction of the two areas is 100cm^2, then:

A_{1}-A_{2}=100cm^{2} \\ (40*r^{2})-(r^{2}*sen(40)*cos(40) )=100cm^{2} \\ 39.51r^{2}=100cm^{2} \\ r^{2}=2.53cm^{2} \\ r=1.59cm

Answer: r= 1.59cm
7 0
3 years ago
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