Answer:
So we already knew all three sides, there are more than one way to do it, for example:
sin∠F = HG/HF = 12/13
cos∠F = GF/HF = 5/13
tan∠F = HG/GF = 12/5
ctg∠F = GF/HG = 5/12
All of them will give you the result which is approximately 67°.
Answer:
The score that separates the lower 5% of the class from the rest of the class is 55.6.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:

Find the score that separates the lower 5% of the class from the rest of the class.
This score is the 5th percentile, which is X when Z has a pvalue of 0.05. So it is X when Z = -1.645.


The score that separates the lower 5% of the class from the rest of the class is 55.6.
There are
7 red balls
8 red balls
1 yellow ball
Hope this helps have a good day! :)