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Goshia [24]
3 years ago
11

I don’t know how to Do this

Mathematics
1 answer:
Debora [2.8K]3 years ago
4 0
Do What? What do you need help with??
You might be interested in
Lauren has finished 25% of the 120 push ups she needs to do for softball
Ilya [14]

Answer:

30 pushups

Step-by-step explanation:

25/100 = x/120

so, 120x25 = 100x

3000 = 100x

3000/100= x

x = 30

so, Lauren has completed 30 push-ups.

3 0
3 years ago
What function is graphed below?<br><br><br><br> y = 2x<br> y = x + 3<br> y = 2x + 3<br> y = 2x + 2
vagabundo [1.1K]

Answer:

y=2x+3

Step-by-step explanation:

The coefficient has to be 2, since the graph has a slope of 2, and the constant has to be 3 because the y- intercept is 3.

y=2x+3

3 0
3 years ago
Read 2 more answers
Convert the following to Standard Form: (x - 5)^2 + 4
netineya [11]

Answer:

x² - 10x + 29

Step-by-step explanation:

The standard form of a quadratic is , ax² + bx + c (a ≠ 0 )

Given

(x - 5)² + 4 ← expand factor using FOIL

= x² - 10x + 25 + 4

= x² - 10x + 29 ← in standard form

5 0
3 years ago
A geometric series has second term 375 and fifth term 81 . find the sum to infinity of series .
Eduardwww [97]

Answer:  \bold{S_{\infty}=\dfrac{3125}{2}=1562.5}

<u>Step-by-step explanation:</u>

  a₁,  375,  a₃,   a₄,  81

First, let's find the ratio (r). There are three multiple from 375 to 81.

375r^3=81\\\\r^3=\dfrac{81}{375}\\\\\\r^3=\dfrac{27}{125}\qquad \leftarrow simplied\\\\\\\sqrt[3]{r^3} =\sqrt[3]{\dfrac{27}{125}}\\ \\\\r=\dfrac{3}{5}

Next, let's find a₁

a_1\bigg(\dfrac{3}{5}\bigg)=375\\\\\\a_1=375\bigg(\dfrac{5}{3}\bigg)\\\\\\a_1=125(5)\\\\\\a_1=625

Lastly, Use the Infinite Geometric Sum Formula to find the sum:

S_{\infty}=\dfrac{a_1}{1-r}\\\\\\.\quad =\dfrac{625}{1-\frac{3}{5}}\\\\\\.\quad =\dfrac{625}{\frac{2}{5}}\\\\\\.\quad = \dfrac{625(5)}{2}\\\\\\.\quad = \large\boxed{\dfrac{3125}{2}}

7 0
3 years ago
In the figure below, segment AC is congruent to segment AB:
stepladder [879]

Answer: A. "Segment AD bisects angle CAB." is the right answer.

Step-by-step explanation:

Given : In ΔABC ,AC≅AB.

⇒∠ACB=∠CBA....(1) (∵ angles opposite to equal sides of a triangle are equal )

Now in ΔACD and ΔABD

AD=AD (common)....(2)

Here we need one more statement to prove the triangles congruent that is only statement (A) fits in it.

If AD bisects ∠CAB then ∠CAD=∠BAD..(3)

Now again Now in ΔACD and ΔABD

∠ACB=∠CBA [from (1)]

AD=AD [common]

∠CAD=∠BAD [from (3)]

So by ASA congruency criteria ΔADC≅ΔABD.

7 0
3 years ago
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