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sattari [20]
3 years ago
11

Last year, a lighting supplier called Bright Idea shipped a total of 37,220 lamps to its distributors. This year, the supplier s

hipped 29,776 lamps. What is the percent of decrease in the number of lamps shipped annually?
Mathematics
1 answer:
fredd [130]3 years ago
7 0

Answer:

25%

Step-by-step explanation:

Given data

Last years shipment= 37220  lamps

These years shipment= 29776 lamps

% Decrease= Initial-Final/Initial*100

% Decrease= 37220-29776/29776*100

% Decrease= 7444/29776*100

% Decrease= 0.25*100

% Decrease= 25%

Hence the decrease is 25%

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Answer:

5 hours

Step-by-step explanation:

Step one:'

given data

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Deborah charges a one time fee of $25 plus $20 per hour

y= 25+20x----------------2

equate 1 and 2 to find x

50+15x=25+20x

collect like terms

50-25= 20x-15x

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divide both sides by 5

x= 25/5

x= 5 hours

4 0
3 years ago
I have no idea what this is can someone please help
siniylev [52]
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That’s one answer.

Hope it helps!
4 0
2 years ago
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A bag contains 15 coins consisting of quarters and dimes. The total value of the coins is $2.55. Which system of equations can b
denis23 [38]

Answer: d+q= 2.55

or d=15+q

I believe this is how you do it

Step-by-step explanation:

5 0
3 years ago
Daija wants trim 3.5centimetes from her hair how should she move the decimal point to convert this number to millimeters
cestrela7 [59]

9514 1404 393

Answer:

  right

Step-by-step explanation:

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5 0
3 years ago
Please help to solve the question​
FinnZ [79.3K]

\:  \:  \: \:  \:     \blue{\underline{\underline{ \large{ \tt{ \red{✧A \: N \: S \: W \: E \: R}}}}}}

\large{ \tt{✽  Step - By - Step \:Explanation}} :

\underline{ \underline{ \large{ \tt{G \: I\: V \: E \: N}}} }:

  • C.P of two mobile set = Rs 55555
  • Profit % on selling 1 mobile = 10%
  • Loss % on selling another mobile = 10%

\underline{ \underline{ \large{ \tt{S\: O \: L \:V \:I \: N \: G}} }}....

\begin{array}{  |c| c | } \tt{Case \: I}& \text{Case \: II}  \\  \hline \hline  \tt{CP = x} &  \tt{ CP = 55555 - x} \\  \tt{Profit\% =10   }  & \tt{Loss\% = 10\%} \\\   \tt{SP_{1} =   \frac{cp(100 + P\%)}{100} }\\    &   \tt{SP_{2} =  \frac{cp(100 - L\%)}{100}   }\\   = \tt{\frac{x(100 + 10)}{10} }  &  =   \tt{\frac{9 \cancel{0}(55555 - x)}{1 \cancel{00}}}  \\  \\ =  \frac{11}{10}  x  &  =   \tt{\frac{499995 - 9x}{10}} \end{array}

\underline{ \large{ \tt{According \: To \:Question \: (ATQ)}} }:

\large{ \tt{ SP_{1} =  SP_{2}}}

⤏ \large{ \tt{ \frac{11}{10} x =  \frac{499995 - 9x}{10}}}

⤏ \large{ \tt{110x = 4999950 - 90x}}

⤏ \tt{110x + 90x = 4999950}

⤏ \large{ \tt{200x = 4999950}}

⤏ \large{ \tt{x =  \frac{4999950}{200}}}

⤏ \large{ \tt{x = 24999.97}}

\large{ \tt{Replacing \: Value}} :

⤏ \large{ \tt{ SP = 2( \frac{11}{10 } \times 24999.97) = \underline{Rs \: 54999.934}}}

\large{ \tt{CP = Rs \: 55555}}

Since SP < CP , he / she made a loss

\large{ \tt{Loss\% =  \frac{CP- SP}{CP}  \times 100\% }}

⟶ \large \tt \:  \frac{55555 - 54999.934}{55555}  \times 100\%

⟶ \large{ \tt{0.99\%}}

⟶\boxed{ \large{ \tt{1\%}}}

Hence , Loss percent = 1%

Hope I helped ! ♕

Have a wonderful day / night ! ツ

✏\underbrace{ \overbrace{  \mathfrak{Carry \: On \: Learning}}} !!

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

3 0
3 years ago
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