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3 years ago

What is the price per oz to the nearest cent of the least expensive: 15 oz for $3.58 or 25 oz for $4.25?

Mathematics

2 answers:

nasty-shy [4]3 years ago

6 0

Answer:

25 oz for $4.25 is less expensive

Step-by-step explanation:

15 oz for $3.58 or 25 oz for $4.25

To find the cost of 1 oz we divide the cost by the number of ounce

15 oz for $3.58

$\frac{3.58}{15}$ = 0.23867 is the cost of 1 oz

25 oz for $4.25

$\frac{4.25}{25}$ = 0.17 is the cost of 1 oz

the cost of second one is less expensive

So 25 oz for $4.25 is less expensive

Bingel [31]3 years ago

3 0

Unit prices 3.58/15 and 4.25/25 dollars per ounce.
That is, 0.2387 and 0.17 dollars per ounce, the second one being the least expensive.

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Question 9 (1 point)

Romashka [77]

Answer:

Step-by-step explanation:

League A League B

151.12 163.25

148 157

26.83 24.93

29 136

136 145

167 178

207 256

League A in ascending order :

26.83 , 29 , 136, 148 , 151.12 , 167,207

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{26.83+29 +136+ 148+ 151.12+ 167+207}{7}\\\\Mean =123.564$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=148

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(26.83-123.564)^2+(29-123.564)^2+.......+(207-123.564)^2}{7}}=63.98$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 26.83 , 29 , 136, 148

n = 4

Q1=82.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 148 , 151.12 , 167,207

n = 4

Q3=159.06

IQR = Q3-Q1=159.06-82.5=76.56

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(82.5-1.5\times 76.56,159.06+1.5\times 76.56)$

(-32.34,273.9)

So, There is no outlier

Maximum = 207

League B in ascending order :

24.93,136,145,157,163.25,178,256

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{24.93+136+145+157+163.25+178+256}{7}\\\\Mean =151.45$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=157

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(24.93-151.45)^2+(136-151.45)^2+.......+(256-151.45)^2}{7}}=68.42$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 24.93,136,145,157

n = 4

$Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}\\Median = \frac{\frac{4}{2} \text{th term}+(\frac{4}{2}+1) \text{th term}}{2}\\Median = \frac{2 \text{th term}+3 \text{th term}}{2}\\Median = \frac{136+145}{2}=140.5$

Q1=140.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 157,163.25,178,256

n = 4

Q3=170.625

IQR = Q3-Q1=170.625-140.5=30.125

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(140.5-1.5\times 30.125,170.625+1.5\times 30.125)$

(95.3125,215.8125)

24.93 and 256 are outliers

Maximum = 256

5 0

3 years ago

A carpenter can make at most 20 tables and at most 30 chairs per day. Each

baherus [9]

Answer:Its B

Step-by-step explanation:

6 0

3 years ago

The school gym can hold 650 people. A permanent bleacher in the gymn holds 136 people. The event organizers are setting up 25 ro

igomit [66]

650 -136=514
514 divided by 25 = 20.56
So it would be 21
This will give you a little extra chairs but they have to be equal in each row

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3 years ago

Yoko runs 7 miles in 50 minutes at the same rate how many miles would she run in 75 minutes

Vsevolod [243]

Answer: 10.5 miles

Step-by-step explanation: If she runs 7 miles for 50 minutes, if you half it, she runs 3.5 miles in 25 minutes. This means if you add 7 and 3.5 miles, you would add 50 and 25 minutes,

So 10.5 miles in 75 minutes in your answer

6 0

3 years ago

Read 2 more answers

Can someone please help me figure out how to do this problem. We have tried several different ways and none of them come up as b

Ilya [14]

Answer:

Step-by-step explanation:

Order of operations: PEMDAS (parentheses, exponents, multiplication, division, addition, subtraction)

5(9)+2(6) ÷ 3 + $5^{2}$