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antoniya [11.8K]
3 years ago
12

What is 134,500 rounded to the nearest ten thousand

Mathematics
2 answers:
Lina20 [59]3 years ago
6 0
130,000 because when you round 1-4 is rounded down and 5-9 is rounded up. If you were to round to the nearest ten thousand then you would look at the 134 and round down
algol133 years ago
6 0
130,000 because it is lower than 5 grand so you would round down because it is less than halfway to 140,00. Hope this helps
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. Laser tag costs $35 per game. The laser tag fans want to play more than 1 game of laser tag. Write an expression to help you f
8_murik_8 [283]

Let x represent the amount of games played.

When x is used, it need to be multiplied by the price ($35).

x(35) = cost in $

Hope this helped :)

3 0
3 years ago
Is 11/2 and 6/11 equivalent? Plz I need the help☹️
trapecia [35]

For this case we have the following fractions:

\frac {11} {2}\\\frac {6} {11}

We must rewrite the fractions, using the same denominator.

We have then:

We multiply the first fraction by 11 in the numerator and denominator:

\frac {11} {2} \frac {11} {11}

We multiply the second fraction by 2 in the numerator and denominator:

\frac {6} {11} \frac {2} {2}

Rewriting we have:

For the first fraction:

\frac {121} {22}

For the second fraction:

\frac {12} {22}

We note that:

\frac {121} {22}> \frac {12} {22}

Answer:

The fractions are not equivalent:

\frac {11} {2}> \frac {6} {11}

5 0
3 years ago
Find a particular solution to the nonhomogeneous differential equation y′′+4y=cos(2x)+sin(2x).
I am Lyosha [343]
Take the homogeneous part and find the roots to the characteristic equation:

y''+4y=0\implies r^2+4=0\implies r=\pm2i

This means the characteristic solution is y_c=C_1\cos2x+C_2\sin2x.

Since the characteristic solution already contains both functions on the RHS of the ODE, you could try finding a solution via the method of undetermined coefficients of the form y_p=ax\cos2x+bx\sin2x. Finding the second derivative involves quite a few applications of the product rule, so I'll resort to a different method via variation of parameters.

With y_1=\cos2x and y_2=\sin2x, you're looking for a particular solution of the form y_p=u_1y_1+u_2y_2. The functions u_i satisfy

u_1=\displaystyle-\int\frac{y_2(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\int\frac{y_1(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx

where W(y_1,y_2) is the Wronskian determinant of the two characteristic solutions.

W(\cos2x,\sin2x)=\begin{bmatrix}\cos2x&\sin2x\\-2\cos2x&2\sin2x\end{vmatrix}=2

So you have

u_1=\displaystyle-\frac12\int(\sin2x(\cos2x+\sin2x))\,\mathrm dx
u_1=-\dfrac x4+\dfrac18\cos^22x+\dfrac1{16}\sin4x

u_2=\displaystyle\frac12\int(\cos2x(\cos2x+\sin2x))\,\mathrm dx
u_2=\dfrac x4-\dfrac18\cos^22x+\dfrac1{16}\sin4x

So you end up with a solution

u_1y_1+u_2y_2=\dfrac18\cos2x-\dfrac14x\cos2x+\dfrac14x\sin2x

but since \cos2x is already accounted for in the characteristic solution, the particular solution is then

y_p=-\dfrac14x\cos2x+\dfrac14x\sin2x

so that the general solution is

y=C_1\cos2x+C_2\sin2x-\dfrac14x\cos2x+\dfrac14x\sin2x
7 0
3 years ago
In six years Xavier will be 3 times older than Joanne is today. Joanne is 24. How old is Xavier?
Elza [17]

Answer:

72

Step-by-step explanation:

7 0
3 years ago
A rectangle and a triangle with the same base and height have the same area.
OverLord2011 [107]
The answer is false because if you attach to triangles together in a way so that the figure would have 4 straight lines, you will get a rectangle. that means half of a rectangle is a triangle, so the area of both cannot be the same even if they have the same base and height.


for example the base and height of both is 3cm and 5cm.

area of the rectangle then would be,
area= base× height
=3cm×5cm=15cmsquared

then the area of the triangle would be,
area= base×height divided by 2
=3cm×5cm÷2= 7.5cm

so your answer is false
hope this helps....
5 0
3 years ago
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