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Ann [662]
3 years ago
9

Dr. Brown did 6 experiments at 7AM. Dr. Rachal did 8 experiments at 6PM. They both had 564 tools each. Dr. Brown used 386 and Dr

. Rachal used 236. How many more experiments do they do with the tool? How many tools are left?
Mathematics
1 answer:
devlian [24]3 years ago
7 0

Answer:

Step-by-step explanation:

Total number of tools for both = 564.

Dr Brown used 386 tools for 6 experiments.

average number of tools per experiment used by Dr Brown = \frac{386}{6}

                                               = 64\frac{1}{3}

Dr Rachal used 236 tools for 8 experiments.

average number of tools per experiment used by Dr Rachal = \frac{236}{8}

                                                = 29\frac{1}{2}

i. The number of more experiment that can be done by Dr Brown = (564 - 386) ÷ (64\frac{1}{3})

                                 = 2.7668

Dr Brown can do two more experiments.

The number of more experiments that can be done by Dr Rachal = (564 - 236) ÷ (29\frac{1}{2})

                                  = 11.1186

Dr Rachal can do 11 more experiments.

ii. Number of tools left after Dr Brown's experiments = 564 - 386

                                                            = 178

Number of tools left after Dr Rachal's experiments = 564 - 236

                                                            = 328

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Answer:

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Step-by-step explanation:

In Statistics, estimated intervals are given with some confidence level. In this example person develop the interval with 97% confidence.

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7 0
3 years ago
If DE = 37 cm and EF = 16 cm, then what are the possible lengths for DF so that DE,EF, and DF can form a triangle? Explain your
chubhunter [2.5K]

Answer:

The length of DF must be between 21 and 53.

Step-by-step explanation:

In a triangle, the length of two sides added together must exceed the length of the 3rd side. So, since EF is the shortest of the two givens, we know that EF + DF must be greater than DE. So we can plug in these numbers to find the minimum.

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Now, for the upper maximum, we know that the two given lengths must be greater than the length of DF. So again, we can solve for the maximum using the amounts.

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4 0
3 years ago
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Crazy boy [7]

Answer: Solution: a=\dfrac{-19}{3} and b=\dfrac{1}{3} .

Step-by-step explanation:

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