Answer:
Any number which is on left side on the line number is less than the number which is on right hand side relative to that number.
As -28 is on the right hand side of the line number, and -162 is heading towards left hand side relative to -28.
Therefore, -28 is greater than -162.
Step-by-step explanation:
To determine:
Is -28 greater than or less than -162?
Solution Steps:
- In mathematics, a number line is considered to be a straight line with numbers placed at equal intervals along its length.
- A number line could be extended infinitely in any direction i..e -∞ to +∞.
- A number is usually represented horizontally.
Any number which is on left side on the line number is less than the number which is on right hand side relative to that number.
As -28 is on the right hand side of the line number, and -162 is heading towards left hand side relative to -28.
Therefore, -28 is greater than -162.
In other words,

Keywords: number line, less than, greater than
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Answer:
The rectangular form of
is
.
Answer:
In this equation, we can start by understanding that "x" has a value of 8, as given in the ordered pair. When multiplied by 5, this leads to "40 - 2y = 30". Next, we can subtract 40 from both sides of the equation. This leads us to a value of "-2y = -10". The next step would be to divide both sides by -2 as a way of isolating "y", which leads us to a final value of "y = 5". The final ordered pair would be (8,5).
XII should be your answer.
<h2>
Hello!</h2><h2>
Let me help you.</h2>
As I understand, you need to write an equation that relates
. This problem will be solved using equations. The problem states:
<em>Nick bought t candies and divided them equally between his y friends and me. Each of us got 7 candies.</em>
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From this statement, we know that:
t: Number of candies Nick bought.
y: Number of friends.
Since I am included in this problem, the number of people involved here can be expressed as:

Since each of us got 7 candies, then it is true that:

<em>So t (number of candies) is a function of y(number of friends).</em>