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const2013 [10]
3 years ago
15

the graph of liner function f passes through the point (1,-9) ad has a slope of -3 what is the zero of f

Mathematics
1 answer:
KiRa [710]3 years ago
4 0

Answer:

answer is 4 im pretty sure

Step-by-step explanation:

did da math

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Will give brainliest !!!! Help asap
olasank [31]

Answer:

a worker with 15 years of service gets 5 weeks of vacation each year, D

3 0
3 years ago
What are the zeros of f(x)=x^2-12+36
DochEvi [55]

Answer:

x = 6

Step-by-step explanation:

I think it's supposed to be

y = x² - 12x + 36

Set the equation equal to zero and solve...

0 = x² - 12x + 36

Now factor.  What 2 numbers add to -12, and multiply to 36?

-6 and -6, so our factors are

0 = (x - 6)(x - 6)

So

0 = x - 6, then

6 = x

3 0
3 years ago
Full steps and all reasons, thanks!​
Nataly_w [17]

You can focus on the two sub-triangles ABC and ACD

We know that they are both right triangles, because we're given that AC and BD are perpendicular.

The sides AB and AD are the hypothenuses of these triangles, so we know their length through the pythagorean theorem:

AD^2 = AC^2+CD^2

AB^2 = AC^2+BC^2

But since we're given BC=CD, the expressions for AD and AB are actually the same expression. This proves that AD=AB, and thus that the triangle is isosceles.

8 0
4 years ago
Find the LCM of 6 and 8 and list the multiples <br>​
Hitman42 [59]

Answer:

24

Step-by-step explanation:

6x4

8x3

8 0
3 years ago
PLEASE HELP!!! Write the equation of a line that goes through the point (6, 3) and is perpendicular to the line y = 4x + 1.
Tpy6a [65]

For this case we have that by definition, the equation of a line in the point-slope form is given by:

y-y_ {0} = m (x-x_ {0})

Where:

m: It is the slope of the line and (x_ {0}, y_ {0})is a point through which the line passes.

We have the following equation of the slope-intersection form:

y = 4x + 1

Where the slope is m = 4

By definition, if two lines are perpendicular then the product of their slopes is -1.

Thus, a perpendicular line will have a slope:

m_ {2} = \frac {-1} {m_ {1}}\\m_ {2} = \frac {-1} {4}\\m_ {2} = - \frac {1} {4}

Thus, the equation will be of the form:

y-y_ {0} = - \frac {1} {4} (x-x_ {0})

Finally we substitute the given point and we have:

y-3 = - \frac {1} {4} (x-6)

Answer:

Option B

8 0
3 years ago
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