Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60

t=1
Step-by-step explanation:
Given function is y = –x.
Substitute the values of x in the function and find the values of y.
y = –x
At x = –2,
y = –(–2) = 2
At x = –1,
y = –(–1) = 1
At x = 0,
y = –(0) = 0
At x = 1,
y = –1(1) = –1
At x = 2,
y = –(2) = –2
Now, substitute the values of y in the table.
The image of the table is attached below.
What don't you get about the problem ?
Answer: C, 3 HOURS
Step-by-step explanation:
she canoed for 1 hour and windsurfed for 2 hours