The probability of dry weather (D) = 1⁄2, rain (R) = 1⁄3 and snow (S) = 1⁄6

Mathematics

1 answer:

g100num [7]3 years ago

6 0

<h3>Answer: 9/20</h3>

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Explanation:

Define the following events

D = weather is dry
R = weather is rainy
S = weather is snowy
L = person is late
T = person is on time

We are given the following probabilities

P(D) = 1/2
P(R) = 1/3
P(S) = 1/6

Then we're further told that "if it is dry, then the probability someone will arrive on time is 4/5". We can condense that into the notation

P(T given D) = 4/5

The "given D" means that we know 100% that event D has occurred. So we're seeing how event T behaves because of D occurring. In other words P(T given D) is the same as saying "What is P(T) when we know D has happened?"

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The instructions also mention that "If it rains, the probability someone is on time is 2/5" tells us we have the notation

P(T given R) = 2/5

And also, the probability someone is on time if it is snowy is

P(T given S) = 1/10

due to it saying "If it snows, the probability that someone will arrive on time is 1/10".

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To recap so far, your teacher told you these three conditional probabilities

P(T given D) = 4/5
P(T given R) = 2/5
P(T given S) = 1/10

They are conditional due to the "given" as part of the probability. They depend on the given event happening.

Subtract each fraction from 1 and we end up with these complementary probabilities

P(L given D) = 1/5
P(L given R) = 3/5
P(L given S) = 9/10

I'm using the idea that P(A)+P(B) = 1, where A and B are complementary events. One or the other event must happen. Either you are on time, or you are late.

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Recall the conditional probability formula is

P(A given B) = P(A and B)/P(B)

which rearranges to

P(A and B) = P(A given B)*P(B)

We'll use this idea to get the following