Which expression is equal to (−4x2−1)(2x2+3)?

2 answers:

7 0

Answer:

The first one:

−8x4−14x2−3

Step-by-step explanation:

(-4•2-1)(2•2+3)

-4•2 = -8

-8 - 1 = -9

(-9)(2•2+3)

2•2 = 4

4+3 = 7

(-9)(7) = -63

Now we find the one that equals -63:

-8•4-14•2-3

(-8•4)-14•2-3

-32-14•2-3

-32-(14•2)-3

-32-28-3

(-32-28)-3

-60-3

-60-3 = -63

BAM! THE ANSWER!

soldi70 [24.7K]3 years ago

3 0

Answer:

The firs one is the right one

Step-by-step explanation:

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Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be $\mathbf{ax^{2}+bx+c=0}$ where x is the variable.

Completing the square method is as follows:

send the constant term to other side of equal $\mathbf{ax^{2}+bx=-c}$
divide the whole equation be coefficient of $\mathbf{x^{2}}$ , this will give $\mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}$
add $\mathbf{(\frac{b}{2a})^{2}}$ to both side of equality $\mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}$
Make one fraction on the right side and compress the expression on the left side $\mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}$
rearrange the terms will give the vertex form of standard quadratic equation $\mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}$