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2 years ago

PLEASE HELP ASAP WORTH A LOT OF MY GRADE

Mathematics

1 answer:

ella [17]2 years ago

6 0

Answer:

Step-by-step explanation:

Im almost positive its d because for triangles you multiply by radical two for when its 45 degrees then the side for the one part of the triangle would be 26 radical 2 multiplied by 39 to get 1397.243 then you double that to get d

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3.5y−12=1.5(y−2)<br> A) One solution<br> B) No solution<br> C) Infinite solutions

Montano1993 [528]

Answer:

Step-by-step explanation:

3.5y - 12 = 1.5y - 3

2y -12 = -3

2y = 9

y = 4.5

the answer is a. one solution

5 0

3 years ago

When working with inequalities what do you do when its x squared > 16 and vice versa does the sign flip.

S_A_V [24]

Answer:

$x4$

$\{x\in \mathbb{R}| \:\left(-\infty \:,\:-4\right)\cup \left(4,\:\infty \:\right) \}$

Step-by-step explanation:

$x^2>16$

$x\sqrt{16}$

$x4$

The interval notation will be:

$\{x\in \mathbb{R}| \:\left(-\infty \:,\:-4\right)\cup \left(4,\:\infty \:\right) \}$

The contrary,

$x^2$

is $-4$

6 0

3 years ago

Read 2 more answers

Solve the equation x^2-4x+85=0

lara [203]

Can't factor
use quadratic
for
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

given
1x^2-4x+85=0
a=1
b=-4
c=85

x= $\frac{-(-4)+/- \sqrt{(-4)^2-4(1)(85)} }{2(1)}$
x= $\frac{4+/- \sqrt{16-340} }{2}$
x= $\frac{4+/- \sqrt{-324} }{2}$
x= $\frac{4+/- (\sqrt{-1})(\sqrt{324}) }{2}$
remember that √-1=i
x= $\frac{4+/- i(\sqrt{324}) }{2}$
x= $\frac{4+/- i(18) }{2}$
x=2+/-9i

x=2+9i or x=2-9i

3 0

3 years ago

I need help thanks in advance

sergij07 [2.7K]

Answer:

Step-by-step explanation:

The rule is if 2 chords intersect inside a circle, then the measure of the angle formed is one half the um of the measure of the arcs intercepted by the angle and its vertical angle. In other words, angle TSU = 1/2(arc TU + arc MV):

angle TSU = 1/2(90 + 80) and

angle TSU = 1/2(170) and

angle TSU = 85

6 0

3 years ago

⦁ Explain how you could use the construction tool or a compass and straightedge to create a line segment that is twice as long a

lara [203]

Answer:

u can be using it at perpendicular and place it's center on point A

hope that helps a bit-

5 0

2 years ago