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allsm [11]
4 years ago
7

2x+3y=0 and x+2y=-1 Solve by substitution

Mathematics
1 answer:
dmitriy555 [2]4 years ago
8 0

Answer:

The solution of the given equations is (-3,2)

Step-by-step explanation:

<u>Step:1</u>

The Given equations are 2 x+3 y=0 .......(1)

                                          x+2 y-1 =0.........(2)

<u>Step 2:-</u>

Solving<u> </u>both equations by using substitution method

multiply equation (2) with number '2' ,  

2 x+4 y-2=0.......(3)

subtracting the equations (1) and (3) and cancelled 'x' terms

we get 3y-4y=0-2

y=2

<u>Step 3:</u>-

substitute y= 2 in equation (1) we get

2 x+3 y=0

2 x+3(2)=0

2 x=-6

x=-3

<u>Final answer</u>:-

The solution of the given equations is (-3,2)

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Jake has a rectangular garden that measures 12 feet by 14 feet. He wants to increase the area by 50% and plans to increase each
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<em>In order to increase the area of a rectangular garden that measures 12 feet by 14 feet by 50% Jake must increase each dimension by equal lengths, x:</em>

x\approx 2.9ft

<h2>Explanation:</h2><h2 />

First of all, let's calculate the area of the original rectangular garden:

A=b\times h \\ \\ b:base \\ \\ h:height \\ \\ \\ b=12ft \\ \\ h=14ft \\ \\ \\ A=12(14) \\ \\ A=168ft^2

Jake wants to increase the area by 50%, so the new area would be:

A'=168(1.5) \\ \\ A'=252ft^2

He wants to increase the area by 50% and plans to increase each dimension by equal lengths, x, so this is represented by the figure below, therefore:

(12+x)(14+x)=252 \\ \\ 168+12x+14x+x^2-252=0 \\ \\ x^2+26x-84=0 \\ \\ \\ Using \ quadratic \ formula: \\ \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ a=1 \\ \\ b=26 \\ \\ c=-84 \\ \\ \\ x=\frac{-26 \pm \sqrt{26^2-4(1)(-84)}}{2(1)} \\ \\ x=\frac{-26 \pm \sqrt{1012}}{2} \\ \\ \\ Two \ solutions: \\ \\ x_{1}=-13+\sqrt{253} \approx 2.9\\ \\ x_{2}=-13-\sqrt{253} \approx -28.9 \\ \\ x_{2} \ is \ discarded \ because \ it \ can't \ be \ negatives

Finally:

<em>In order to increase the area of a rectangular garden that measures 12 feet by 14 feet by 50% Jake must increase each dimension by equal lengths, x:</em>

x\approx 2.9ft

<h2>Learn more:</h2>

Dilation: brainly.com/question/10945890

#LearnWithBrainly

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