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BaLLatris [955]
3 years ago
11

The question reads The graph of y=f(x) is shown below (dashed curve). Manipulate the green draggable points to obtain the graph

of y=f(-x+4)-5 (solid curve). Someone help me please!!!

Mathematics
1 answer:
Sedbober [7]3 years ago
4 0

Answer:

Don’t know the answer

Sorry

You might be interested in
Plz help me well mark brainliest!!
gregori [183]

Answer:

x=-52

1/3x-2/3=-18

multiply both sides by 3

x-2=-54

x=-54+2

x=-52

4 0
3 years ago
Read 2 more answers
100p for an answer please
Rainbow [258]
So from solving the problem, we know that the answer must equal -28.

When you solve all of the given options, we find that the only one that does equal -28 would be A.) (-6)(4) + (-6)(2/3).

When I doubt, solve it out. I hope I could help!
7 0
3 years ago
Help please!!
stepladder [879]

Answer:

it changed 21 Fahrenheit

Step-by-step explanation:

-14.8 - 6.2 = -21

and minus + minus = +

so, -14.8 + 21 = 6.2

i think so that is the right answer

4 0
2 years ago
Let x be 3 <br> 4 + x + x + x = ?
IRINA_888 [86]

Answer:

13

Step-by-step explanation:

We replace each X with a 3, so

4 + 3 + 3 + 3

which equals to 13

7 0
3 years ago
I need help Please help.
asambeis [7]

Answer:

Step-by-step explanation:

Number of students 10

Problem 1. $625 for the bus hire per friday, So 625*4=$2500

Problem 2. 2500/25=$100 each for the whole 4 weeks

Problem 3.

10 students tickets 220= 2200 for all tickets. The bus, 625/10 = $62.5*4= $250 dollars for the whole 4 weeks for the bus so in all each student pays $470 each

20 students, tickets 220=4400 for all tickets. The bus, 625/20=$31.25*4=$125 for the whole 4 weeks for the bus, so in all each student must pay $345 each

30 students, tickets 220 = 6600 for all tickets. The bus, 625/30 =$20.83*4=$83.32 for the whole 4 weeks for the bus, so in all each student must pay $303.32 each

41 students, tickets $160=$6560 for all tickets. The bus, because you need 2 buses at 625 each so $1250 for both buses 1250/41= 30.49*4=$121.96 for the whole 4 weeks for the bus. So in al each student must pay $281.96 each

Hope this is correct

8 0
3 years ago
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