Answer:
(a) $4250,
(b) $5225.
Step-by-step explanation:
Let n represent number of months.
We have been given that John saves $3500 the first month and every month later decreases it by $75.
First of all, we will find formula of John's savings in n months using arithmetic progression, where, 1st term is 3500 and common difference is 75.
, where,
n = Number of terms in a sequence,
d = Common difference.
(a) To find John's savings in 11 months, we will substitute in above formula.
Therefore, John would have saved $4250 in the 11th month.
(b) To find John's savings after 2 years, we will substitute in above formula.
Therefore, John would have saved $5225 in 2 years.
Answer: x = -2, y = -5
Step-by-step explanation: There you go btw wanna trade r o b l o x acc.
The answer is:
6x = 48
x = 8
Answer:
<h2>x = 2 or x = -5</h2>
Step-by-step explanation:
Answer:
Step-by-step explanation:
This is a test of 2 population proportions. Let 1 and 2 be the subscript for the men and women who own cats respectively. The population proportion of men and women who own cats would be p1 and p2 respectively.
p1 - p2 = difference in the proportion of men and women who own cats.
The null hypothesis is
H0 : p1 = p2
p1 - p2 = 0
The alternative hypothesis is
Ha : p1 ≠ p2
p1 - p2 ≠ 0
it is a two tailed test
Sample proportion = x/n
Where
x represents number of success
n represents number of samples
For men
n1 = 80
p1 = 55/100 = 0.55
x1 = p1n1 = 0.55 × 80 = 44
For women,
n2 = 100
p2 = 30/100 = 0.3
x2 = p2n2 = 0.3 × 100 = 30
The pooled proportion, pc is
pc = (x1 + x2)/(n1 + n2)
pc = (44 + 30)/(80 + 100) = 0.41
1 - pc = 1 - 0.41 = 0.59
z = (p1 - p2)/√pc(1 - pc)(1/n1 + 1/n2)
z = (0.55 - 0.3)/√(0.41)(0.59)(1/80 + 1/100) = 3.39
Test statistic = 3.39