Answer:
Step-by-step explanation:
This is a test of 2 population proportions. Let 1 and 2 be the subscript for the men and women who own cats respectively. The population proportion of men and women who own cats would be p1 and p2 respectively.
p1 - p2 = difference in the proportion of men and women who own cats.
The null hypothesis is
H0 : p1 = p2
p1 - p2 = 0
The alternative hypothesis is
Ha : p1 ≠ p2
p1 - p2 ≠ 0
it is a two tailed test
Sample proportion = x/n
Where
x represents number of success
n represents number of samples
For men
n1 = 80
p1 = 55/100 = 0.55
x1 = p1n1 = 0.55 × 80 = 44
For women,
n2 = 100
p2 = 30/100 = 0.3
x2 = p2n2 = 0.3 × 100 = 30
The pooled proportion, pc is
pc = (x1 + x2)/(n1 + n2)
pc = (44 + 30)/(80 + 100) = 0.41
1 - pc = 1 - 0.41 = 0.59
z = (p1 - p2)/√pc(1 - pc)(1/n1 + 1/n2)
z = (0.55 - 0.3)/√(0.41)(0.59)(1/80 + 1/100) = 3.39
Test statistic = 3.39
