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svetoff [14.1K]
3 years ago
9

Amount of available mates is considered a limiting factor. True or False?

Biology
1 answer:
kumpel [21]3 years ago
4 0

Answer:

true

Explanation:

I think it's True, I hope its right

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yellow flowered plant is crossed with red one; some of the offspring had orange color phenotype . explain what happened?​
allochka39001 [22]

Answer:

incomplete dominance

Explanation:

the offspring is different from the parent

8 0
3 years ago
ОО.0 О.
Anna71 [15]

The olfactory epithelium is a specialized epithelial tissue inside the nasal cavity that is involved in smell. In humans, it lies on the roof of the nasal cavity about 7 cm above and behind the nostrils.

6 0
2 years ago
Cnidarians and Ctenophores are alike in the following way: a) they are scavengers and parasites. b) they are both diploblastic.
alexandr1967 [171]

Answer:

Options B.

They are both diploblastic.

Explanation:

Cnidarians are group of aquatic animals that live both in fresh water and Marine water. They are distinguished by the possession of specialized cells called cnidocytes for capturing prey. They are radially symmetrical and have two body layers ectoderm and endoderm separated by jelly layer called mesoglea.

Examples are Hydra, corals, sea anemone and jelly fish.

Ctenophores are phylum of Marine animals that are found in every where. They are characterized by vast of cilia which is use for swimming. They are bilaterally symmetrical , they have mouth and don't have anus. They don't have respiratory, excretory and circulatory system. They are diploblastic i.e they have two body layers but some are triploblastic.

They have nemacyctes for capturing prey.

Examples are nuda, tentaculata e.t.c.

7 0
2 years ago
Mr. Fuller assigned his science class a lab comparing the masses of objects to the nearest gram using a balance. The mass of a p
AleksAgata [21]
D) 20 should be correct

6 0
3 years ago
Glucose is present in blood plasma at a concentration of approximately 80 mg/dL. A typical 70 kg human has approximately 5 L blo
tester [92]

Answer: 48.93 mL of sprite

Volume of blood in 7 Kg human = 5 L

Percentage of plasma in blood = 55%

Volume of plasma in 5 L blood =  (1 L = 10 dL)

Concentration of glucose in plasma = 80 mg/dL

Amount of glucose present in 27.5 dL : 80 mg /dL × 27.5 dL= 2200 mg

Let the volume of sprite with 2200 mg glucose be x

Concentration of glucose in sprite = 44.96 mg/mL

Explanation:

5 0
3 years ago
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