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boyakko [2]
3 years ago
14

A client is receiving an intravenous infusion of 1000 mL of normal saline with 40 mEq of potassium chloride. The care unit is mo

nitoring the client for signs fo hyperkalemia. Which finding initially will be noted in the client if hyperkalemia is present?
Biology
1 answer:
qaws [65]3 years ago
5 0

Answer:

The correct answer is nausea and breathing trouble.

Explanation:

In the given example, the client is receiving 1000ml saline with 40mEq of KCl (Potassium Chloride) and we are looking for symptoms of hyperkalemia. Hyperkalemia is a disease observed when there is excess amounts of potassium present in the bloodstream. It's first and most important symptoms are tiredness, nausea and vomiting, breathing trouble and chest pain so these are the findings that will be initially noted in the client if they have hyperkalemia.

I hope this answer helps.

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What is a prokaryote, and when did prokaryotes arise?
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3 years ago
Sophie says dolphins and sharks look very similar, so they must be related. Jake disagrees, saying DNA evidence has shown that d
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According to modern classification I will say that Jake is correct. With the use of tracing back and DNA technology then we can say that this is the digital way which is used nowadays to classify animals.

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3 years ago
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A nurse and a nursing student are discussing the plan of care for a patient with schizophrenia. The patient, who has been taking
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Answer:

Because this may be an exacerbation of psychosis, the provider may increase the dose of the FGA.

Explanation:

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5 0
3 years ago
In a hardy-weinberg population with two alleles, a and a, that are in equilibrium, the frequency of allele a is 0.2. what is the
Allushta [10]
The Hardy-Weinberg equation is as follows:
( {p + q})^{2}  = 1
{p}^{2}  +2pq +   {q}^{2}  = 1
Where:
(convert all % to decimals)

p= homozygous dominant
q= homozygous recessive
pq= heterozygous

While you did not specify whether the 0.2 frequency was for dominant or recessive, we can still figure out the answer.

Using the 1st equation, we can solve for the other dominant/recessive frequency:

1-0.2=0.8

Meaning that:

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If the heterozygouz frequency is 2pq, then it becomes a simple "plug & chug" sort of approach.

2(0.8)(0.2)= 2(0.16)= 0.32

So, the heterozygous frequency would be:
0.32

Hope this helps!
8 0
3 years ago
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They both carry a recessive allele for blue eyes because answer A doesnt state anything about the allele dominance, answer B wouldnt be right because if blue eyes was dominant then the mother would have blue eyes as the dominant gene always shows, but she has brown
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