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andriy [413]
3 years ago
10

Naomi plans to attend a four-year college that costs a total of $21,800 per year. Her family invests $9,500 in an account that e

arns 6% annual interest compounded monthly.
If Naomi’s family invests an additional $450 per month for five years, will the value of the account be enough to pay for at least the first two years of college? Use an online periodic deposit calculator.
Mathematics
2 answers:
Elodia [21]3 years ago
6 0
Uhh this is on gooogle :)
ki77a [65]3 years ago
5 0

Answer:

its on google

Step-by-step explanation:

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Answer what? This question? Oh, I'm answering it right now. Did you have another question out? Well, I can't see it. 
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A pool of possible jurors consists of 14 men and 10 women. How many different juries consisting of 5 men and 7 women are possibl
Doss [256]
It is d. 240,240

hope this helps

7 0
3 years ago
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Find the midpoint of segment AB given. A (-3, 2) and B (3, -2)
Tasya [4]

\text{The formula of the midpoint of segment AB:}\\\\\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right).\\\\\text{We have the points}\ A(-3,\ 2)\ \text{and}\ B(3,\ -2).\ \text{Substitute:}\\\\x=\dfrac{-3+3}{2}=\dfrac{0}{2}=0\\\\y=\dfrac{2+(-2)}{2}=\dfrac{0}{2}=0\\\\Answer:\ \boxed{(0,\ 0)}

8 0
3 years ago
Of 580580 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compa
Lubov Fominskaja [6]

Answer:

a) The 99% confidence interval would be given (0.204;0.296).

b) We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

c) No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

Step-by-step explanation:

Part a

Data given and notation  

n=580 represent the random sample taken    

X represent the seafood sold in the country that is mislabeled or misidentified by the people

\hat p=0.25 estimated proportion of seafood sold in the country that is mislabeled or misidentified by the people

\alpha=0.01 represent the significance level (no given, but is assumed)    

p= population proportion of seafood sold in the country that is mislabeled or misidentified by the people

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.25 - 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.204

0.25 + 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.296

And the 99% confidence interval would be given (0.204;0.296).

Part b

We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

Part c

A government spokesperson claimed that the sample size was too​ small, relative to the billions of pieces of seafood sold each​ year, to generalize. Is this criticism​ valid?

No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

4 0
4 years ago
There are 10 fish in the pond.Some of them swim away.There are 3 fish left.How many fish are left in the pond? Show all your thi
OleMash [197]

10

Just because the fish swam away doesn't mean they left the pond

4 0
3 years ago
Read 2 more answers
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