Slope ~3
y intercept ~7
y= equation ~y=3x+7
Student P:
They messed up in step 1 because they made the 7.75 positive instead of negative, which causes the entire solution to be wrong
Student Q:
They were correct up until step 3. They didn't take all the negatives out of the equation (ex. -(3.5+7.75+29.67)).
Complete set:
From the picture, it looks like the original problem was
-2.5(1.4+3.1)+6.9(-4.3)
Step 1: multiply
1.4(-2.5)+3.1(-2.5)+6.9(-4.3)
Step 2: subtract (add?) them all together
-3.5-7.75-29.67
Step 3 should equal -40.92
T(t)=e−kt(∫ekt[KM(t)+H(t)+U(t)]dt+C)
M is the outside temperature, H is other things that affect temperature
in the tank(0 in this case), and U is the solar panel. K comes from the
time constant, and should be the inverse of the time constant I believe.
T is temperature, t is time.
T(t)=e−164t(∫e164t[164(80)+4t]dt
After integrating I keep getting
−16304+256t+Ce−164t
I calculate C to be 16414 setting t equal to 0 and using the initial conditions
Answer:
The standard deviation of weight for this species of cockroaches is 4.62.
Step-by-step explanation:
Given : A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measuring the weights of many of these cockroaches, a lab assistant reports that 14% of the cockroaches weigh more than 55 grams.
To find : What is the approximate standard deviation of weight for this species of cockroaches?
Solution :
We have given,
Mean 
The sample mean x=55
A lab assistant reports that 14% of the cockroaches weigh more than 55 grams.
i.e. P(X>55)=14%=0.14
The total probability needs to sum up to 1,
The z-score value of 0.86 using z-score table is z=1.08.
Applying z-score formula,
Where, 
is standard deviation
Substitute the values,
The standard deviation of weight for this species of cockroaches is 4.62.
Answer:
0.2915
Step-by-step explanation:
Let W represent water and D represent Dying probability
W = water
D = die
->If with water, it will die with probability 0.4
P(W & D) = 0.82 x 0.4 = 0.328
->Without water the plant will die with probability 0.75
P(W ' & D) = 0.18 x 0.75 = 0.135
Taking sum of the above values with water and without water.
P(D) = P(W & D) + P(W ' & D) = 0.4643
P(W ' | D) = P(W ' & D) / P(D)
= 0.135 /0.463
= 0.2915 ≈ 29.15%
Thus, the probability the neighbor forgot to water is 0.2915
