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Serjik [45]
3 years ago
5

A scientist wants to research the potential spread of germs by contact. she knows that the number of possible handshakes within

a group of n people is given by the equation upper n equals one half left parenthesis n squared minus n right parenthesis . there are 105 people at a party. how many handshakes are​ possible?
Mathematics
1 answer:
Viefleur [7K]3 years ago
8 0
Given that <span>the number of possible handshakes within a group of n people is given by the equation:

</span>N= \frac{1}{2} (n^2-n)
<span>
Given that there are 105 people at a party, the number of possible handshakes is given by:

</span>N= \frac{1}{2} (105^2-105) \\  \\ = \frac{1}{2} (11025-105)=10920<span>
</span>
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Which of the expressions below could be factored quickly using the "difference of squares"? Select all that apply.
boyakko [2]

Answer:

Difference of squares method is a method that is used to evaluate the difference between two perfect squares.

For example, given an algebraic expression in the form:

can be factored as follows:

From the given expressions, the only expression containing two perfect squares with the minus sign in the middle is the expression in option A.

i.e.  

which can be factored as follows:

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Your roommate Dave eats one of two things for breakfast each day. Eighty percent of the time he has eggs for breakfast, and twen
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Answer:

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Step-by-step explanation:

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3 years ago
X+y=12<br> 3x = 2y + 6<br> system of elimination
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Answer:

(x,y)=(6,6)

Step-by-step explanation:

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3 years ago
A store sells bread and milk. On Tuesday, 3 loaves of bread and 2 litres of milk were sold for €6.25. On Thursday
chubhunter [2.5K]

Equation is 4b + 5m = €10.90, and values of b and m are €1.35 and €1.1 respectively.

Step-by-step explanation:

  • Step 1: Find equation for Thursday's sales.

Given b = price of a loaf of bread and m = price of one liter of milk

Total sales = €10.90

Equation ⇒ 4b + 5m = €10.90

  • Step 2: Find the values of b and m.

3b + 2m = 6.25 ----- (1)

4b + 5m = 10.90 ---- (2)

Multiply eq(1) by 5 and eq(2) by 2 to make coefficients of m equal.

15b + 10m = 31.25

8b + 10m = 21.8

Subtract eq(2) from eq(1)

⇒ 7b = 9.45

⇒ b = 9.45/7 = €1.35

Substitute for b and find m using eq(1).

⇒ 3 × 1.35 + 2m = 6.25

⇒ 4.05 + 2m = 6.25

⇒ 2m = 2.2

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8 0
3 years ago
You are at a stall at a fair where you have to throw a ball at a target. There are two versions of the game. In the first
Tomtit [17]

Answer:

P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729

And the probability of loss with the first wersion is 0.729

P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Alternative 1

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=3, p=0.1)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We can find the probability of loss like this P(X=0) and if we find this probability we got this:

P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729

And the probability of loss with the first wersion is 0.729

Alternative 2

Let Y the random variable of interest, on this case we now that:

Y \sim Binom(n=5, p=0.05)

The probability mass function for the Binomial distribution is given as:

P(Y)=(nCy)(p)^y (1-p)^{n-y}

Where (nCx) means combinatory and it's given by this formula:

nCy=\frac{n!}{(n-y)! y!}

We can find the probability of loss like this P(Y=0) and if we find this probability we got this:

P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

4 0
3 years ago
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