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3 years ago

Aight. I know the answer but tell me how to get it if I were to get it again? (It would help me ALOT.)

Mathematics

2 answers:

Lera25 [3.4K]3 years ago

8 0

I’m not really sure..... can you add more to it

daser333 [38]3 years ago

5 0

I think it’s beaker A but am not sure

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If sin(theta) =4/5 and is in quadrant 2, the value of cot(theta

iren [92.7K]

$\sin\theta= \frac{4}{5} 
\\
\\\sin^2\theta+\cos^2\theta=1
\\ \cos\theta=\pm \sqrt{1-\sin^2\theta} =\pm \sqrt{1-( \frac{4}{5})^2 } =\pm \sqrt{1- \frac{16}{25} } =\pm \sqrt{\frac{9}{25} }=\pm \frac{3}{5}}$

$\theta \in II \Rightarrow \cos\theta\ \textless \ 0 \Rightarrow \cos\theta=-\frac{3}{5}$

$\cot\theta= \frac{\cos\theta}{\sin\theta}= \frac{-\frac{3}{5}}{\frac{4}{5}} =- \frac{3}{4}$

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3 years ago

4 1/2 + 1 3/5<br><br>in simplest form

slavikrds [6]

The answer is 6.1 = 6 1/10

7 0

3 years ago

What is 99.99/72? Plz help ASAP!

Minchanka [31]

Answer:

1.38875. Please mark as brainliest.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A fish tank has the shape of a rectangular prism. It has a length of 2 1/4 meters, width of 7/8 meters, and a height of 1 1/2 me

ivolga24 [154]

2 61/64m^3; For a rectangular prism, just use the formula V=w h l

V=0.875*1.5*2.25

V=1.3125*2.25

V=2.953125

V=2 61/64m^3

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3 years ago

Using traditional methods, it takes 95 hours to receive a basic flying license. A new license training method using Computer Aid

Snowcat [4.5K]

Answer:

There is not sufficient evidence to support the claim that the technique performs differently than the traditional method.

Step-by-step explanation:

The null hypothesis is:

$H_{0} = 95$

The alternate hypotesis is:

$H_{1} \neq 95$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

A researcher used the technique with 260 students and observed that they had a mean of 94 hours. Assume the standard deviation is known to be 6.

This means, respectively, that $n = 260, X = 94, \sigma = 6$

The test-statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{94 - 95}{\frac{6}{\sqrt{260}}}$

$z = -2.69$

The pvalue is:

2(P(Z < -2.69))

P(Z < -2.69) is the pvalue of Z when X = -2.69, which looking at the z-table, is 0.0036

2*(0.0036) = 0.0072

0.0072 < 0.01, which means that the null hypothesis is accepted, that is, there is not sufficient evidence to support the claim that the technique performs differently than the traditional method.

7 0

3 years ago