Answer:
After 14.92 seconds, the arrow hits the ground.
Step-by-step explanation:
Given:
Initial velocity of the arrow is,
The arrow goes up and come back to the same starting position. So, initial position is same as that of final position.
Therefore, displacement of the arrow is 0 m.
The displacement of the arrow is given as:
(equation 1)
Plug all value in equation 1 and solve for
where
∴ After 14.92 seconds, the arrow hits the ground.
Answer:
The function f(x) = ln(x - 4) is graphed the question options
Step-by-step explanation:
* Lets study the the information of the problem
- The graph of a logarithmic has a vertical asymptote at x=4
* That means the curve gets closer and closer to the vertical line x = 4
but does not cross it
- It contains the point (e+4, 1)
* That means if we substitute x = e + 4 in the equation the value
of y will be equal to 1
- It has an x-intercept of 5
* That means if we substitute y = 0 in the equation the value of x
will be equal to 5
* Lets find the right answer
∵ f(x) = ln(x - 4)
* To find the equation of the asymptote let x - 4 = 0
∵ x - 4 = 0
∴ x = 4
∴ f(x) has a vertical asymptote at x = 4
* Lets check the point (e + 4 , 1) lies on the graph of the f(x)
∵ x = e + 4
∴ f(e+4) = ln(e + 4 - 4) = ln(e)
∵ ln(e) = 1
∴ The point (e+4 , 1) lies on the graph of the function f(x)
* To find the x-intercept put y = 0
∵ f(x) = 0
∴ ln(x - 4) = 0
* Change the logarithmic function to the exponential function
- The base of the ln is e
∴ e^0 = x - 4
∵ e^0 = 1
∴ x - 4 = 1 ⇒ add 4 to the both sides
∴ x = 5
* The function f(x) = ln(x - 4) is graphed the question options
