Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
Answer:
The second one from the top
Step-by-step explanation:
x^(5/3) y^1/3)
The ratio of each vertex coordinate on ΔA'B'C to the corresponding vertex coordinate on ΔABC is equal to 2. For example, A(1, 1) → A′(2, 2). This ratio is equal to the scale factor, n.
Start with the slope formula.
Slope formula can be read as the second y minus the first
y over the second x minus the first x.
So for this problem, the second y minus the first y would be
5 - 2 and the second x minus the first x would be 8 - 4.
5 - 2 over 8 - 4 is 3/4.
So the slope of the line that passes through these points is 3/4.
Neither, they are the same amount. 1,000 milliliters is equal to one liter. As such, 10000/1000 equal 10. So, 10000 mL is equal to 10 L of juice.
