3 years ago

Factor -7v^2-25v-12 show steps

2 answers:

7 0

$- 7 {v}^{2} - 25v - 12 \\ = - 7 {v}^{2} - 21v - 4v - 12 \\ = - 7 v (v + 3) - 4(v + 3) \\ = ( - 7v - 4)(v + 3) \\ = - (7v + 4)(v + 3)$

34kurt3 years ago

3 0

(v-4) ( 7v+3) is the answer

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Answer:

The graph has a domain of all real numbers.

The graph has a y-intercept at $(0,1)$ .

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Step-by-step explanation:

Given: The graph is $y=\sqrt[3]{x-1}+2$

The domain of a function is a set of input values for which the function is real and defined.

Thus, the graph has a domain of $(-\infty, \infty)$ .

To find the y-intercept: To find the y-intercept, substitute $x=0$ in $y=\sqrt[3]{x-1}+2$ .

$\begin{aligned}y &=\sqrt[3]{x-1}+2 \\&=\sqrt[3]{0-1}+2 \\&=-1+2 \\&=1\end{aligned}$

Thus, the y-intercept is $(0,1)$

To find the x-intercept: To find the x-intercept, substitute $y=0$ in $y=\sqrt[3]{x-1}+2$ .

$\begin{aligned}y &=\sqrt[3]{x-1}+2 \\0 &=\sqrt[3]{x-1}+2 \\-2 &=\sqrt[3]{x-1} \\(-2)^{3} &=(\sqrt[3]{x-1})^{3} \\-8 &=x-1 \\-7 &=x\end{aligned}$

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