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Anna007 [38]
3 years ago
6

Need help on this please help

Mathematics
1 answer:
DochEvi [55]3 years ago
4 0
Tides move around Earth as bulges in the ocean. As the ocean bulges toward the moon, a high tide is created. The high tide on the side of Earth facing the moon is called the high high tide. The high tide caused by the bulge on the opposite side of Earth is called the low high tide.
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Solve. You must factor first.<br><br> 2n^2 +9n - 35=0
Ksivusya [100]

Answer:

Step-by-step explanation:

2n² + 9n - 35 = (2n-5)(n+7)

n = 2.5, -7

7 0
3 years ago
Read 2 more answers
Type your answer and then click or tap Done.<br> Simplify -(x-2y) - y.
AlladinOne [14]

Answer:

Step-by-step explanation:

x(x-2y)-(y-x)2  

Final result :

 -y2

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 x • (x - 2y) -  (y - x)2

Step  2  :

2.1     Evaluate :  (y-x)2   =    y2-2xy+x2  

Final result :

 -y2

4 0
3 years ago
Read 2 more answers
(3x^2y^6)^7<br> please help me
DerKrebs [107]

Answer:

I'm not sure but I think the answer is 2187 X^ (14) Y^ ( 42)

Step-by-step explanation:

(3x^2y^6)^7

3^(7) x (X^)^(7) x ( Y ^(6)^(7)

= 2187 X^ 14)Y^( 42)

5 0
3 years ago
Solve this equation: please show all the work<br><br> <img src="https://tex.z-dn.net/?f=x%5E%7B3%7D-y%2B9-%28xy%29" id="TexFormu
puteri [66]
x^{3}  - y + 9 - (xy)
(3)^{3} - (6) + 9 - (3 * 6)
27 - 6 + 9 - 18
12
4 0
3 years ago
A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num
yKpoI14uk [10]

Answer: hypotenuse = c^{2} + b^{2}

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side (s_{1},s_{2}) of the right triangle, .i.e.:

h^{2} = s_{1}^{2} + s_{2}^{2}

In this question:

s_{1} = c^{2}-b^{2}

s_{2} = 2bc

Substituing and taking square root to find hypotenuse:

h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}

Calculating:

h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}

h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}

c^{4}+b^{4}+2b^{2}c^{2} = (c^{2}+b^{2})^{2}, then:

h=\sqrt{(c^{2}+b^{2})^{2}}

h=(c^{2}+b^{2})

Hypotenuse for the right-angled triangle is h=(c^{2}+b^{2}) units

3 0
3 years ago
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