This question is incomplete, the complete question is;
PROBLEM SOLVING WITH PERCENTS: You are planning a wedding reception for 75 guests that will take place in exactly 10 months. There are two different sites that you are contemplating using, with the stipulations on payments as described below. Determine the TOTAL cost of renting each location.
Rental of space = $68 per guest; Down payment = 25% of total cost; Payment due one month before the reception includes a 7.4% interest payment on the balance.
Answer: Total Cost of Renting = $5312.29
Step-by-step explanation:
Given that;
Rental space = $68 per guest, down payment = 25%, 7.4% interest payment on the balance.
Total Cost of Renting = Down Payment + Remaining payment
Total Cost of Renting = $68 × Guests × 25% + ($68 × Guest - Down payment) × (1 + Interest *9/12)
Total Cost of Renting = $68 × 75 × 25% + ($68 × 75 - Down payment) × (1 + 7.40% × 9/12)
Total Cost of Renting = $1275 + ($5100 - 1273) × (1.0555)
Total Cost of Renting = $1275 + 4037.29
Total Cost of Renting = $5312.29
Answer:
The number of dimes is <u>14</u> and the number of quarters is <u>7</u>.
Step-by-step explanation:
Given:
Emily has $3.15 worth of dimes and quarters.
<em><u>She has twice as many dimes as quarters.</u></em>
Now, to determine the number of dimes and the number of quarters.
Let the number of quarters be 
And the number of dimes be 
So, the total worth of dimes and quarters = $3.15.
Now, to get the number of dimes and quarters:
According to question:



<em>Dividing both sides by 0.45 we get:</em>

<em>Thus, the number of quarters</em> = 7.
<em>So, the number of dimes</em> = 
Therefore, the number of dimes is 14 and the number of quarters is 7.
Answer and Step-by-step explanation:
we have the following data:
Point estimate = sample mean = \ bar x = 12.39
Population standard deviation = \ sigma = 3.7
Sample size = n = 177
a) the margin of error with a 90% confidence interval
α = 1 - 90%
alpha = 1 - 0.90 = 0.10
alpha / 2 = 0.05
Z \ alpha / 2 = Z0.05 = 1,645
Margin of error = E = Z \ alpha / 2 * (\ sigma / \ sqrtn)
we replace:
E = 1.645 * (3.7 / \ sqrt177)
Outcome:
E = 0.46
b) margin of error with a 99% confidence interval
α = 1-99%
alpha = 1 - 0.99 = 0.01
alpha / 2 = 0.005
Z \ alpha / 2 = Z0.005 = 2,576
Margin of error = E = Z \ alpha / 2 * (\ sigma / \ sqrtn)
we replace:
E = 2,576 * (3.7 / \ sqrt177)
Outcome:
E = 0.72
c) A larger confidence interval value will increase the margin of error.
Answer:
i believe it's 12 but i'm not entirely sure
Step-by-step explanation:
i hope this helps :) please let me know if it was wrong
have a nice day !!
The area of the triangle below is 7.5 units