-22+(x/35)=-25
add 22 to both sides
x/35=-3
multiply both sides by 35 to cleaf raction
x=-105
number was -105
Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
Find out more solving for distance at brainly.com/question/10739348
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Es la b 1DM 5c 6d 0U
4.350+2.710+3.500= 10.560
Nacieron 10.560 productos en la huerta.
Answer: 39% voted for biking
Step-by-step explanation:
Add the other two percentages and subtract from 100
40 + 21 = 61
100 - 61 = 39