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laila [671]
3 years ago
14

7.Suppose that water is entering a cylindrical water tank so that the initial height of the water is 3 cm and the

Mathematics
1 answer:
lukranit [14]3 years ago
4 0

Answer:

H(t) = 3*2^{t/30}

Step-by-step explanation:

Height doubles at every 30 seconds, so let's call n how many times it happens, and the t the total time:

n = t/30

If the height doubles one time, it is multiplied by 2, if it doubles 2 times, it's multiplied by 2², for n times, it is multiplied by 2ⁿ, so for an initial height equal to 3:

H(t) = 3*2^{t/30}

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to solve this system of equations, first, we substitute the equation y = 3x + 10 to the <em>y </em>variable in the equation 2x-3y = -6. Therefore, we get:

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