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3 years ago

7.Suppose that water is entering a cylindrical water tank so that the initial height of the water is 3 cm and the

Mathematics

1 answer:

lukranit [14]3 years ago

4 0

Answer:

$H(t) = 3*2^{t/30}$

Step-by-step explanation:

Height doubles at every 30 seconds, so let's call n how many times it happens, and the t the total time:

n = t/30

If the height doubles one time, it is multiplied by 2, if it doubles 2 times, it's multiplied by 2², for n times, it is multiplied by 2ⁿ, so for an initial height equal to 3:

$H(t) = 3*2^{t/30}$

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Maru [420]

Answer:

Step-by-step explanation:

n = 12

The mean of the set of data given is

Mean, x = (286 + 290 + 285 + 291 + 287 + 275 + 262 + 289 + 274 + 276 + 297 + 262)/12 = 281.2

Standard deviation = √(summation(x - mean)²/n

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We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

1) For the null hypothesis,

H0: µ = 290

For the alternative hypothesis,

H1: µ < 290

This is a left tailed test.

2) Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 12,

Degrees of freedom, df = n - 1 = 12 - 1 = 11

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µ = population mean = 290

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4) We would determine the p value using the t test calculator. It becomes

p value = 0.0083

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