Answer:
<u>Graph of the equation y = 2/5x - 1</u>
Please check the attached graph of the equation where:
The point (0, -1) represents the y-intercept, it is the point where the line crosses the y-axis.
The point (2.5, 0) represents the x-intercept, it is the point where the line crosses the x-axis.
Step-by-step explanation:
Given the equation
y = 2/5x - 1
<u>Determining the y-intercept:</u>
We know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.
As the equation is given such as
y = 2/5x - 1
substitute x = 0
y = 2/5(0) - 1
y = 0 - 1
y = -1
so the ordered pair (0, -1) represents the y-intercept.
Thus, the y-intercept is: -1
<u>Determining the x-intercept:</u>
We know that the value of the x-intercept can be determined by setting x = y and determining the corresponding value of x.
As the equation is given such as
y = 2/5x - 1
substitute y = 0
0 = 2/5x - 1
2/5x = 1
x = 5/2
x = 2.5
so the ordered pair (2.5, 0) represents the x-intercept.
<u>Graph of the equation y = 2/5x - 1</u>
Please check the attached graph of the equation where:
The point (0, -1) represents the y-intercept, it is the point where the line crosses the y-axis.
The point (2.5, 0) represents the x-intercept, it is the point where the line crosses the x-axis.
A. square root property
it has one value with x which is x^2 and it cn be easily solved without having to factorise, quadratic formula cant be used as it need ax^2+bx+c=0 format
B. factorising
i just felt like this was easier to factorise than the other 2 options left
C. Completing the square
same reason personal preference
D- Quadratic
the 17 kinda threw me off and i didnt wanna get on factorising or doing completing the square so quadratic formal
