If you are smart in ranges, graphs, and functions, pls help me out. Look at the screenshot below!
1 answer:
Answer:
<u>Graph of the equation y = 2/5x - 1</u>
Please check the attached graph of the equation where:
The point (0, -1) represents the y-intercept, it is the point where the line crosses the y-axis.
The point (2.5, 0) represents the x-intercept, it is the point where the line crosses the x-axis.
Step-by-step explanation:
Given the equation
y = 2/5x - 1
<u>Determining the y-intercept:</u>
We know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.
As the equation is given such as
y = 2/5x - 1
substitute x = 0
y = 2/5(0) - 1
y = 0 - 1
y = -1
so the ordered pair (0, -1) represents the y-intercept.
Thus, the y-intercept is: -1
<u>Determining the x-intercept:</u>
We know that the value of the x-intercept can be determined by setting x = y and determining the corresponding value of x.
As the equation is given such as
y = 2/5x - 1
substitute y = 0
0 = 2/5x - 1
2/5x = 1
x = 5/2
x = 2.5
so the ordered pair (2.5, 0) represents the x-intercept.
<u>Graph of the equation y = 2/5x - 1</u>
Please check the attached graph of the equation where:
The point (0, -1) represents the y-intercept, it is the point where the line crosses the y-axis.
The point (2.5, 0) represents the x-intercept, it is the point where the line crosses the x-axis.
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Answer:
The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.
Step-by-step explanation:
Given : The position of an object along a vertical line is given by , where s is measured in feet and t is measured in seconds.
To find : What is the maximum velocity of the object in the time interval [0, 4]?
Solution :
The velocity is rate of change of distance w.r.t time.
Distance in terms of t is given by,
Derivate w.r.t. time,
It is a quadratic function so its maximum is at vertex of the function.
The x point of the function is given by,
Where, a=-3, b=6 and c=7
As 1 lie between interval [0,4]
Substitute t=1 in the function,
Th maximum velocity is 10 ft/s.
Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.