Answer:
The first error that Tomas made was added 6 to both sides of the equation instead of subtracting 6
Step-by-step explanation:
Let
x ----> represents the number of pounds of granola
y ----> represents the number of pounds of walnuts
we know that
The linear equation that represent this scenario is
2x+6y=12 -----> equation A
x=3 -----> equation B
substitute equation B in equation A and solve for y
2(3)+6y=12
6+6y=12
Subtract 6 both sides
6+6y-6=12-6
6y=6
Divide by 6 both sides
6y/6=6/6
y=1
so
The number of pounds of walnuts is 1
therefore
The first error that Tomas made was added 6 to both sides of the equation instead of subtracting 6
Answer:
All of the above
Step-by-step explanation:
dy/dt = y/3 (18 − y)
0 = y/3 (18 − y)
y = 0 or 18
d²y/dt² = y/3 (-dy/dt) + (1/3 dy/dt) (18 − y)
d²y/dt² = dy/dt (-y/3 + 6 − y/3)
d²y/dt² = dy/dt (6 − 2y/3)
d²y/dt² = y/3 (18 − y) (6 − 2y/3)
0 = y/3 (18 − y) (6 − 2y/3)
y = 0, 9, 18
y" = 0 at y = 9 and changes signs from + to -, so y' is a maximum at y = 9.
y' and y" = 0 at y = 0 and y = 18, so those are both asymptotes / limiting values.
Answer:
(x^2 + x -1) x (x^2+3x-3)
Step-by-step explanation:
-6x-5+x^4+4x^3-x^2+8
-6x+3+x^4+4x^3-x^2
-6x+3+x^4+x^3+3x^3-x^2
-3x-3x+3+x^2 x(x^2+x-1)+3x^3 +3x^2-3x^2
3x *(x^2+x+x-2)-3(x^2+x-1)+x^2 *(x^2+x-1)
= (x^2+x-1) x (x^2+3x-3)
* means multiply btw
Step-by-step explanation:
A study was to be undertaken to determine if a particular training program would improve physical fitness. A sample of 31 university students was selected to be enrolled in the fitness program. The researchers wished to determine if there was evidence that their sample of students differed from the general population of untrained subjects. The sample mean is 47.4 and a standard deviation of 5.3. The 98% confidence interval is determined and is given as, (45.2, 49.6) .
If the level of confidence is changed to 95%, then the confidence interval will become shorter but the p-value will not change because it is calculated using the test statistic. So the correct answer is (a).
