Answer:
After completing the square the expression is (x-2)^2 -12 =0 and real solution are x = 5.46 and x = -1.46
Step-by-step explanation:
We need to complete the square:
x^2 − 4x − 8 = 0
x^2 -2(x)(2)+(2)^2 -8 -4 =0
(x^2 -4x +4) - 12 = 0
(x-2)^2 -12 =0
Now, finding the value of x
(x-2)^2 -12 =0
(x-2)^2 = 12
taking square root on both sides
So, After completing the square the expression is (x-2)^2 -12 =0 and real solution are x = 5.46 and x = -1.46
We know that
[area of a circle ]=pi*r²
diameter=4 in
r=4 in/2-----> 2 in
so
area=pi*2²-----> area of the circle=4*pi in²
the answer is
the area, in square inches, of the circle is <span>3.14 • 2²</span>
Answer:
x = 7
Step-by-step explanation:
Assuming the quadrilateral is a parallelogram, then the diagonals bisect each other.
7x - 8 = 41
7x = 49
x = 7
Answer:
Maria: (50 bulbs)/(2 hours) = 25 bulbs/hour
Lois: (45 bulbs)/(3 hours) = 15 bulbs/hour
Together: 25 + 15 = 40 bulbs/hour
(150 bulbs)/(40 bulbs per hour) = 3 3/4 hours
(3/4 hours)(60 minutes/hour) = 45 minutes
Total time: 3 hours 45 minutes
We know that
<span>Since the focus and vertex are above and below each other, rather than side by side, I know that this ellipse must be taller than it is wide.
</span>Then
a²<span> will go with the </span>y<span> part of the equation
</span>Also, since the focus is 8 <span>units below the center, then </span><span>c = 8
</span>since the vertex is 17<span> units above, then </span><span>a = 17
</span>The equation b²<span> = a</span>²<span> – c</span>²<span> gives me
</span>b²=17²-8²-----> b²=225
the equation is
y²/a²+x²/b²=1------> y²/289+x²/225=1
the answer isy²/289+x²/225=1see the attached figure
