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Hunter-Best [27]
3 years ago
12

True or False: The additive inverse (opposite) of (a^2-2a+3) is (-a^2+2a-3)

Mathematics
1 answer:
kirill115 [55]3 years ago
5 0

Answer:

true

Step-by-step explanation:

You might be interested in
X + 3x² – 28x <br><br> Can you guys help me solve this in ax^2+bx+c <br> Thank you thank you
Molodets [167]

Answer:

3x²+(-27x) +0

Step-by-step explanation:

The given expression is :

x + 3x² – 28x

We need to solve this in the form of ax²+bx+c.

we can write the given expression as :

3x²-28x+x = 3x²-27x

= 3x²+(-27x) +0

If we compare the given expression with the general expression, we find that,

a = 3, b = -27 and c = 0

Hence, the required equation is 3x²+(-27x) +0.

3 0
3 years ago
The interior angles of a triangle have measures k°, 27°, and 10°.<br><br> What is the value of k?
NikAS [45]

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~

Assuming that the sum of all the angles must equal 180°

180 - (27+10) = k

180 - 37 = k

k = 143°

6 0
3 years ago
A salesperson’s commission rate is 4%. What is the commission from the sale of $39,000 worth of furnaces? Suppose sales would do
kenny6666 [7]

Answer:

The earnings will double

Step-by-step explanation:

Step one:

given data

we are told that the sales person's earnings is 4% of the sales made.

given that the sales made is $37,000 worth of furnaces.

Step two:

we want to find 4% of $37,000

=4/100*37000

=0.04*37000

=1480

hence for $37,000 the earning will be $1480.

Now suppose sales is doubled that is 37000*2= 74000

we want to find 4% of $74,000

=4/100*74000

=0.04*74000

=2960.

the earnings is $2960.

So if sales doubles the earnings will double

3 0
3 years ago
Consider the sequence defined recursively by do = 0, an = an-1 + 3n – 1. a) Write out the first 5 terms of this sequence,
creativ13 [48]

Answer:

The first 5 terms of the sequence is 2,7,15,26,40.

Step-by-step explanation:

Given : Consider the sequence defined recursively by a_0=0 a_n=a_{n-1}+3n-1

To find : Write out the first 5 terms of this sequence ?

Solution :

a_n=a_{n-1}+3n-1 and a_0=0

The first five terms in the sequence is at n=1,2,3,4,5

For n=1,

a_1=a_{1-1}+3(1)-1

a_1=a_{0}+3-1

a_1=0+2

a_1=2

For n=2,

a_2=a_{2-1}+3(2)-1

a_2=a_{1}+6-1

a_2=2+5

a_2=7

For n=3,

a_3=a_{3-1}+3(3)-1

a_3=a_{2}+9-1

a_3=7+8

a_3=15

For n=4,

a_4=a_{4-1}+3(4)-1

a_4=a_{3}+12-1

a_4=15+11

a_4=26

For n=5,

a_5=a_{5-1}+3(5)-1

a_5=a_{4}+15-1

a_5=26+14

a_5=40

The first 5 terms of the sequence is 2,7,15,26,40.

5 0
3 years ago
Graph the solution of y - 4 &lt; 2 on a number line.
Luda [366]

Answer:

y<6

Step-by-step explanation:

You will solve it like a one-step equation but just leave the less then symbol. so anything less then 6 is your answer

3 0
3 years ago
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