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photoshop1234 [79]

3 years ago

13

Raymond used 36 cubes to build the first layer of a rectangular prism. The edge length of each cube was 1 inch. The finished pri

sm had a total of 8 layers. What is the volume of Raymond's prism in cubic inches?

1 answer:

zhuklara [117]3 years ago

6 0

Answer:

$Volume = 288in^3$

Step-by-step explanation:

Given

$Base\ Cubes = 36$

$Layers = 8$

Required

The volume of the prism

The number of base cubes represents the base area and the number of layers represents the height of the prism.

So, the volume is calculated as:

$Volume = Base\ Cubes * Layers$ i.e Base Area * Heights

$Volume = 36 * 8$

$Volume = 36in^2 * 8in$

$Volume = 288in^3$

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It’s interval. It will be right.

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3 years ago

Please help me with this. I will give brainliest.

Dennis_Churaev [7]

Answer:

(X-6, y-3)

Step-by-step explanation:

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3 years ago

Determine all prime numbers a, b and c for which the expression a ^ 2 + b ^ 2 + c ^ 2 - 1 is a perfect square .

kogti [31]

Answer:

The family of all prime numbers such that $a^{2} + b^{2} + c^{2} -1$ is a perfect square is represented by the following solution:

$a$ is an arbitrary prime number. (1)

$b = \sqrt{1 + 2\cdot a \cdot c}$ (2)

$c$ is another arbitrary prime number. (3)

Step-by-step explanation:

From Algebra we know that a second order polynomial is a perfect square if and only if $(x+y)^{2} = x^{2} + 2\cdot x\cdot y + y^{2}$ . From statement, we must fulfill the following identity:

$a^{2} + b^{2} + c^{2} - 1 = x^{2} + 2\cdot x\cdot y + y^{2}$

By Associative and Commutative properties, we can reorganize the expression as follows:

$a^{2} + (b^{2}-1) + c^{2} = x^{2} + 2\cdot x \cdot y + y^{2}$ (1)

Then, we have the following system of equations:

$x = a$ (2)

$(b^{2}-1) = 2\cdot x\cdot y$ (3)

$y = c$ (4)

By (2) and (4) in (3), we have the following expression:

$(b^{2} - 1) = 2\cdot a \cdot c$

$b^{2} = 1 + 2\cdot a \cdot c$

$b = \sqrt{1 + 2\cdot a\cdot c}$

From Number Theory, we remember that a number is prime if and only if is divisible both by 1 and by itself. Then, $a, b, c > 1$ . If $a$ , $b$ and $c$ are prime numbers, then $2\cdot a\cdot c$ must be an even composite number, which means that $a$ and $c$ can be either both odd numbers or a even number and a odd number. In the family of prime numbers, the only even number is 2.

In addition, $b$ must be a natural number, which means that:

$1 + 2\cdot a\cdot c \ge 4$

$2\cdot a \cdot c \ge 3$

$a\cdot c \ge \frac{3}{2}$

But the lowest possible product made by two prime numbers is $2^{2} = 4$ . Hence, $a\cdot c \ge 4$ .

The family of all prime numbers such that $a^{2} + b^{2} + c^{2} -1$ is a perfect square is represented by the following solution:

$a$ is an arbitrary prime number. (1)

$b = \sqrt{1 + 2\cdot a \cdot c}$ (2)

$c$ is another arbitrary prime number. (3)

Example: $a = 2$ , $c = 2$

$b = \sqrt{1 + 2\cdot (2)\cdot (2)}$

$b = 3$

4 0

3 years ago

blondinia [14]

Answer:

b- 13 weeks

Step-by-step explanation:

She makes $550 a week but spends $200 on merchandise so her total weekly is technically $350 in order to earn profit she has to get more than $4500

divide $4500 by $350 which you will get 12.6 but you round it to 13 meaning it would take her a maximum of 13 weeks to receive profit

3 0

3 years ago

A triangle has one side that measures 1 foot and another side that measures 20 inches. What are possible lengths of the third si

klio [65]

Answer:

The correct options for the possible lengths of the third side are;

13 inches

28 inches

Step-by-step explanation:

The given lengths of two sides of the triangle are;

The length of one side of the triangle = 1 foot = 12 inches

The length of the other side of the triangle = 20 inches

The question can be solved by the triangle inequality theorem as follows;

A + B > C

B + C > A

A + C > B

Let the given sides be A = 12 inches and B = 20 inches

We have;

12 + 20 = 32 > C

Therefore, by the triangle inequality theorem, the third side, 'C', is less than 32 inches

Similarly, when C = 6 inches, we have;

A + C = 12 + 6 = 18 < B = 20

Therefore, the third side cannot be 6 inches

when C = 13 inches, we have;

A + C = 12 + 13 = 25 > B = 20

Therefore, the third side can be 13 inches

when C = 28 inches, we have;

A + C = 12 + 28 = 30 > B = 20

Therefore, the third side can be 28 inches

4 0

3 years ago