Step-by-step answer:
We are looking at the coefficient of the 22nd term of (x+y)^25.
Following the sequence, first term is x^0y^25, second term is x^1y^24, third term is x^2y^23...and so on, 22nd term is x^21y^4.
The twenty-second term of (x+y)^25 is given by the binomial theorem as
( 25!/(21!4!) ) x^21*y^4
=25*24*23*22/4! x^21y^4
= 12650 x^21 y^4
The coefficient required is therefore 12650, for a binomial with unit valued coefficients.
For other binomials, substitute the values for x and y and expand accordingly.
Question would have been more clearly stated if the actual binomial was given, as commented above.
Answer:
24 = x
Step-by-step explanation:
You use Pythagorean theorem. Since the normal equation is 
, you already have the 
and another side which can be 
or 
.
Because you have the hypotenuse and a side , your equation looks like this now: 
and when you solve for be you just subtract 
to get 24.
The answer is 0.50.
P(4<=X<=8)=P(x=4)+ P(x=5)+ P(x=6)+ P(x=7)+ P(x=8)= 0.05+ 0.15+0.15+0.15 +0 = 0.50
Notice that in 8 the line touches the x axis so it’s corresponding probability is 0.
