Answer:
Substitute -8 as x into the equation.
h(-8)=-2(-8+5)^2+4
h(-8)=-2(-3)^2+4
h(-8)=-2(9)+4
h(-8)=-18+4
h(-8)=-14
:)
Answer:
The cost of one pass is 25$
Step-by-step explanation:
Call the cost of one of the passes, P. So we have
63 = 13 + 2P - subtract 13 from both sides
50 = 2P - divide both sides by 2
25 = P
So the cost of one pass = $25
(2x + 3y = 12) x (-2)
(4x - 3y = 6) x 1
-4x - 6y = -24
4x - 3y = 6
You can cancel out the x values by adding the two equations together.
(-4x + 4x) + (-6y - 3y) = (-24 + 6)
-9y = -18
y = 2
Solve for x now...
4x - 3(2) = 6
4x - 6 = 6
4x = 12
x = 3
Check... (x = 3, y = 2)
2(3) + 3(2) = 12
6 + 6 = 12
12 = 12 <- this works!
4(3) - 3(2) = 6
12 - 6 = 6
6 = 6 <- this works!
The first one! It is using the distributive or associative property!
