You have to divide 28 by two, then times the answer (14) by five, making it 70
The number of orders Michael, Rafael and Amanda served are 16.8, 33.6, and 41.6 servings
respectively.
<h3>Equation</h3>
- Michael = x
- Rafael = 2x
- Amanda = 2x + 8
- Total servings = 92 orders
x + 2x + (2x + 8) = 92
3x + 2x + 8 = 92
5x = 92 - 8
5x = 84
x = 84/5
x = 16.8 servings
Therefore,
Michael = x
= 16.8 servings
Rafael = 2x
= 2(16.8)
= 33.6 servings
Amanda = 2x + 8
= 33.6 + 8
= 41.6 servings
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Answer: Cool!ididnt even no that!
Step-by-step explanation:
Answer:
x=5
Step-by-step explanation:
9x^2 - 2x + 25 = 8x^2 + 8x
9x^2-8x^2-2x-8x+25=0
x^2-6x+25=0 factorize
(x-5)(x-5)=0
x-5=0 then x=5
Answer:

Step-by-step explanation:
The equations are:


The two graphs intersect when:



To find the area under the curve for the first equation:

To find the area under the curve for the second equation:

To find the total area:

Simplifying the equation:

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).