The equation for the base is that of a circle, so the cross sections will have a leg of length equal to the vertical distance between its halves.
x² + y² = 16 ⇒ y = ±√(16 - x²)
⇒ length = √(16 - x²) - (-√(16 - x²)) = 2 √(16 - x²)
Cross sections with thickness ∆x have a volume of
1/2 length² ∆x = 1/2 (2 √(16 - x²))² ∆x = (32 - 2x²) ∆x
since they are isosceles triangles and so their bases and heights are equal.
Then the total volume would be (D)
Answer: (2,11)
Step-by-step explanation:
To find the point where the functions will intersect, we want to find the place that they are equal to each other. We do this by setting the equations equal to each other.
5x+1=-2x+15 [add both sides by 2x]
7x+1=15 [subtract both sides by 1]
7x=14 [divide both sides by 7]
x=2
Now, we know that the functions intersect at x=2. To find the point, we would plug x back into both equations to ensure that the points are the same.
f(2)=5(2)+1 [multiply]
f(2)=10+1 [add]
f(2)=11
The point on f(x) is (2,11).
g(2)=-2(2)+15 [multiply]
g(2)=-4+15 [add]
g(2)=11
The point on g(x) is (2,11).
Since the point at x=2 is the same for f(x) and g(x), we know that the graph intersects at (2,11).
Answer:
The answer is 1.
Step-by-step explanation:
If it is 5 or more, you round up. If it is 4 or less, you keep it the same.
Answer:
300000+50000+5000+600+40+5
word form:- three lakh fifty five thousand six hundred forty five.
