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3 years ago

10. The figure below is a uniform cross-section of a hall 20 m long and 7 m wide.

Mathematics

1 answer:

tamaranim1 [39]3 years ago

5 0

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Arc AB is One-sixth of the circumference of a circle. What is the radian measure of the central angle? StartFraction pi over 6 E

oksian1 [2.3K]

Answer:

StartFraction pi Over 3 EndFraction

Step-by-step explanation:

we know that

The circumference of a circle subtends a central angle of 360 degrees or 2π radians

by proportion

Find out the central angle for an arc equal to One-sixth of the circumference of a circle

Let

x -----> the measure of the central angle in radians for an arc equal to One-sixth of the circumference

$\frac{C}{2\pi}=\frac{(C/6)}{x}\\\\x=2\pi(C/6)/C\\\\x=\frac{2\pi}{6}$

Simplify

$x=\frac{\pi}{3}$

therefore

StartFraction pi Over 3 EndFraction

5 0

3 years ago

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in one season, a basketball team won 50 games and lost 40 game. what is the ratio of games won to games lost

Colt1911 [192]

I think that the ratio of the game is 7.2 because if you do A+B=C (D)
A=50 B=40 C=90 D=7.2
C= the amount of all the games

7 0

3 years ago

The expression 6x - 3 represents the total number of stuffed animals Deena has in her collection. She decides to put the

jeyben [28]

Answer:

2x-1 (simplest)

Step-by-step explanation:

First put parentheses around 6x-3

The expression is (6x-3)/3

Simplify 2x-1

Make sure you divide both terms though (common mistake only dividing 1)

6 0

3 years ago

A market research company conducted a survey to find the level of affluence in a city. They defined the category "affluence" for

malfutka [58]

Answer:

A 95% confidence interval for this population proportion is [0.081, 0.159].

Step-by-step explanation:

We are given that a market research company conducted a survey to find the level of affluence in a city.

Out of 267 persons who replied to their survey, 32 are considered affluent.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of people who are considered affluent = $\frac{32}{267}$ = 0.12

n = sample of persons = 267

p = population proportion

Here for constructing a 95% confidence interval we have used One-sample z-test for proportions.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.12-1.96 \times {\sqrt{\frac{0.12(1-0.12)}{267} } }$ , $0.12+1.96 \times {\sqrt{\frac{0.12(1-0.12)}{267} } }$ ]

= [0.081, 0.159]

Therefore, a 95% confidence interval for this population proportion is [0.081, 0.159].

4 0

3 years ago

What is the simplified form of x + 8 / 4 - x + 5 / 4

xxTIMURxx [149]

Answer:

I think it is d

Step-by-step explanation:

5 0

3 years ago

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