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3 years ago

6

(5.2×10−2)×(8.0×10−4)=

2 answers:

Digiron [165]3 years ago

4 0

3800. go to math papa.

r-ruslan [8.4K]3 years ago

3 0

<span>(5.2×10−2) × (8.0×10−4) = 3800.

</span>

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HElp me find the IQR please

patriot [66]

The interquartile range is 4

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2 years ago

Gnoma [55]

Answer:

1.5

Step-by-step explanation:

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2 years ago

A carpenter is assigned the job of expanding a rectangular deck where the width is one-fourth the length. the length of the deck

anzhelika [568]

Alright, lets get started.

Suppose the original deck size: width = x feet

the width is one-fourth the length given in question means length = 4 x feet

Means the originally area = $x * 4 x = 4 x^{2}$

Now the dimensions are changed.

New dimensions, width = (x + 6)

new length = (4x+10)

So, new area will be = $(x+6) * (4x+10) = 4x^{2} + 10 x + 24 x + 60 = 4x^{2} + 34 x + 60$

the area of the new rectangular deck is 128 ft2 larger than the area of the original deck, means

$4x^{2} + 128= 4x^{2} + 34 x + 60$

Subtracting $4x^{2}$ from both sides

$128 = 34 x + 60$

Subtracting 60 from both sides

$128 - 60 = 34 x + 60 - 60$

$68 = 34 x$

Dividing 34 in both sides

$\frac{68}{34} = \frac{34 x }{34}$

$x = 2$

Means width = 2 feet

Length would be = 4 time width = 4 * 2 = 8 feet

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Hope it will help :)

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3 years ago

A study of recent records of car accidents revealed that average proportion of drivers who were distracted by their phones at th

aksik [14]

Answer:

At least 547 records need to be studied.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

And the margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence interval

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $z = 1.96$ .

In this problem, we have that:

$M = 0.04, p = 0.35$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.35*0.65}{n}}$

$0.04\sqrt{n} = 0.93486$

$\sqrt{n} = 23.37$

$n = 546.2275$

At least 547 records need to be studied.

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3 years ago

likoan [24]

2,100,000 Centimeters

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2 years ago